Question

A garden that is 14 feet by 17 feet will have a pedestrian pathway on the border, making the combined area of the garden and the border 311 square feet what is the width of the pathway

Answer 1

Answer:

The width of the pathway is 5.2 feet

Step-by-step explanation:

Given that the shape of the garden and the walkway is a rectangle, the walkway would have the same length as the garden but would have it's own width.

Let the width of the garden be W and that of the walkway be t while the length of both the garden and walkway is L. The combined area A

= L( W + t)

Given that the combined area of the garden and the border 311 square feet while the garden is  14 feet by 17 feet

311 = 14 (17 + t)

311 = 238 + 14t

collect like terms

14t = 311 - 238

14t = 73

t = 73/14

= 5.2 feet