If a number is a multipule of 6 then it is a multiplule of 2 AND 3
if a number is a multiplule of 2 then the last digit should be divisible by 2 (ie, 0,2,4,6,8)
if a number is divisible by 3, then the sum of its digits is divisble by 3
try each
A. 333
last number is not divisible by 2 so not divisible by 6
B. 882
2 is divisible by 2
8+8+2=18
18/3=6
divisible by 6 yes
C. 424
4 is disibielbe by 2
4+2+4=10
10/3=not a whole number so not divisible by 6
D. 106
6 is divisible by 2
1+0+6=7
7/3= not a whole number so not divibislb eby 6
answer is B
Answer:

Hence, ption B is true.
Step-by-step explanation:
Given the expression

solving the expression

as


so the expression becomes

Group like terms

Add similar elements

Therefore, we conclude that:

Hence, option B is true.
Answer:
180 cars
Step-by-step explanation:
Like you can see in the picture, I like to set up a proportion, so 81 over X and 45 over 100. Then, you can cross multiply, so 81 x 100 = 8100 and then divide, 8100 ÷ 45 = 180, your answer!
G = (7h + 2f + 3c - 17.15)/2