Answer:
The Sum Of The Integers From -6 To 58 is <u>1690.</u>
Step-by-step explanation:
Given,


We have to find out the sum of integers from -6 To 58.
Firstly we will find out the total number of terms that is 'n'.
Here 

Now we use the formula of A.P.

On substituting the values, we get;

So there are 65 terms in between -6 To 58.
That means we have to find the sum of 65 terms in between -6 To 58.
Now we use the formula of Sum of n_terms.

On substituting the values, we get;

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>
Answer:
I'm late but the answer to the question on the left is 21 and the answer to the question on the right is 3.
Step-by-step explanation:
Remember that you have to complete the equations in order of PEMDAS.
19-3×4÷(-6)
For this equation, you would do 3×4 first (which equals 12) then divide that by -6 (Which equals - 2) and finally you would subtract that from 19. 19 - (-2)= 21
6(-8) / -12 - 1
For this equation you would do 6(-8) first (which equals -48) then divide that by -12 (which equals 4) and finally subtract 1 from that 4. 4-1=3
The correct answer for this question is this one:
<span>On a piece of paper, use a protractor and a ruler to construct △ABC with AB=6 cm , m∠A=80° , and m∠B=50° .
What is AC ?
3 cm
<u>6 cm</u>
9 cm
12 cm</span>
If you try to draw the triangle, it forms an isosceles triangle.
side AB has a length of 6cm. Side AB = Side AC. So the length of Side AC is also 6 cm.
Hope this helps answer your question and have a nice day ahead.
(x,y)=(64/81, 70/81) I can provide a description if needed. I used the process of elimination.