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Alexeev081 [22]
3 years ago
10

How long does it take an account with a principal of $600 to earn $90 in interest at a simple annual interest rate of 5%

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
Long really long really do you think you can slide
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This would be y = |x+1| + 3
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2 years ago
What is 36% of 745? Show work
kogti [31]
745/x=100/36
<span>(745/x)*x=(100/36)*x
</span><span>745=2.7777777777778*x
</span>(2.7777777777778) to get x
<span>745/2.7777777777778=x </span>
<span>268.2=x </span>
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8 0
3 years ago
ASAP I NEED HELP
alexdok [17]

The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:

y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.

Substituting the given info into the equation y-k = a(x-h)^2, we get:

3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is

y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.

7 0
2 years ago
One side of a square is 445mm long.find the perimeter in m​
sergejj [24]
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3 0
3 years ago
The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning ca
Fed [463]

Answer:

Sam had a finish time with a z-score of -2.93.

Karen had a finish time with a z-score -1.91.

Sam had the more convincing victory.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sam:

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.

So \mu = 186.94, \mu = 0.372, X = 185.85

Z = \frac{X - \mu}{\sigma}

Z = \frac{185.85 - 186.94}{0.372}

Z = -2.93

Sam finishing time was 2.93 standard deviations below the mean.

Sam had a finish time with a z-score of -2.93.

Karen:

The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

So \mu = 110.7, \sigma = 0.115, X = 110.48

Z = \frac{X - \mu}{\sigma}

Z = \frac{110.48 - 110.7}{0.115}

Z = -1.91

Karen finishing time was 1.91 standard deviations below the mean.

Karen had a finish time with a z-score -1.91.

Who had the more convincing victory?

Sam finishing time was 2.93 standard deviations below the mean.

Karen finishing time was 1.91 standard deviations below the mean.

Sam finished more standard deviations below the mean than Karen, that is, he was faster relative to his competition than Karen.

So Sam had the more convincing victory.

8 0
3 years ago
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