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3 years ago

Plsss need help asap

Mathematics

1 answer:

I am Lyosha [343]3 years ago

7 0

Answer: I believe it’s -2
I’m not sure
Step by step explanation:

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AlladinOne [14]

W + 2w = 60

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3 years ago

Find the Domain: <br> {(-5, 3), (-1,0), (3, -4), (-1, 2)}

Marrrta [24]

Answer:

(-1,2) is domain

Step-by-step explanation:

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3 years ago

Solve this inequality: 3p – 16 < 20.

mamaluj [8]

P<12 would be the answer to this question.

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2 years ago

Please help me now!!!!!!!!!!!

Thepotemich [5.8K]

Answer:

Calculate the slope in the four intervals.

m = (f(b) - f(a)) / (b - a) slope in Intervall [a; b]

m1 = (3 - 0) / (2 - 0) = 1.5

m2 = (11 - 3) / (4 - 2) = 4

m3 = (23 - 3) / (6 - 2) = 5

m4 = (23 - 11) / (6 - 4) = 6

between x = 4 and x = 6 is the correct answer.

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3 years ago

Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet

Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

$f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\$

Take the second derivative of the function, to check if it will given a minimum perimeter

$\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)$

Determine the critical points of the first derivative;

df/dw = 0

$\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m$

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0

2 years ago