Answer: 11
Students have both a brother and a sister
Step-by-step explanation:
I don't think probability should be used for this question because the answer is quite clear
So in a class of 25 students
5 students don't have a sibling
So 25-5=20
Total number of siblings=14+17=31 siblings in total
So 20 people have 31 siblings
31-20=11
So the answer should be 11
The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].
Hope this helps.
Answer:
Step-by-step explanation:
2 (3x - 1) + 2 (2x^2 + x + 9)
6x - 2 + 4x^2 +2x + 18
4x^2 + 8x +16
