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Stolb23 [73]
3 years ago
8

Oscar draws two lines on his paper. The lines are always one inch apart and do not intersect. Which term can be used to name wha

t Oscar drew?
Mathematics
1 answer:
kaheart [24]3 years ago
7 0

Answer:

Parralel lines

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Can help me for homework pleas
Rasek [7]
Hey You!

32 / 8 = 4

4 × 7 = 28

20. ANSWER:

The fish swims 28 feet deep.

21. ANSWER:

Numerator;Denominator

22. ANSWER:

439 / 3 = 146.3333 repeat.

So, each individual computer costs more than each individual printer.

6 0
3 years ago
Read 2 more answers
What is the area of a square rug that measures 6 feet on a side
erastovalidia [21]

Answer:

36

Step-by-step explanation:

A square has equal sides.

Area= lenth * width

6*6=36

4 0
3 years ago
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Student records suggest that the population of students spends an average of 6.30 hours per week playing organized sports. The p
Ymorist [56]

Answer:

a) 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

b) 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

Step-by-step explanation:

To solve this question, it is important to know the Normal probability distribution and the Central Limit Theorem

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 6.3, \sigma = 2.1, n = 49, s = \frac{2.1}{\sqrt{49}} = 0.3

A) What is the chance HLI will find a sample mean between 5.5 and 7.1 hours?

This is the pvalue of Z when X = 7.1 subtracted by the pvalue of Z when X = 5.5.

By the Central Limit Theorem, the formula for Z is:

Z = \frac{X - \mu}{s}

X = 7.1

Z = \frac{7.1 - 6.3}{0.3}

Z = 2.67

Z = 2.67 has a pvalue of 0.9962

X = 5.5

Z = \frac{5.5 - 6.3}{0.3}

Z = -2.67

Z = -2.67 has a pvalue of 0.0038

So there is a 0.9962 - 0.0038 = 0.9924 = 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

B) Calculate the probability that the sample mean will be between 5.9 and 6.7 hours.

This is the pvalue of Z when X = 6.7 subtracted by the pvalue of Z when X = 5.9

X = 6.7

Z = \frac{6.7 - 6.3}{0.3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 5.9

Z = \frac{5.9 - 6.3}{0.3}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918.

So there is a 0.9082 - 0.0918 = 0.8164 = 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

5 0
3 years ago
Algebra solve each equation (30 points)
Hitman42 [59]
They all 3 have no solution!
8 0
2 years ago
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A cylinder has a radius of 5 cm and a height of 12 cm, what is the volume?
nika2105 [10]

Step-by-step explanation:

In a cylinder

  • Radius=r=5cm
  • Height=h=12cm

We know that

\boxed { \sf \: volume = \pi {r}^{2} h} \\  \rm \rightharpoonup \:  \frac{22}{7}  \times  {5}^{2}  \times 12 \\  \rm \rightharpoonup \:  \frac{22}{7}  \times 25 \times 12 \\  \rm \rightharpoonup \:  \frac{6600}{7}  \\  \rm \rightharpoonup \: 942.8cm {}^{3}

3 0
2 years ago
Read 2 more answers
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