The ground temperature started at 10 degrees.
The rate was: for every 1000 meters (m) of going above the ground, the temperature dropped 5 degrees, meaning that it got cooler.
The ratio is 1000 meters to 5 degrees
So that would mean: 10-5-5-5-5-5=-15 degrees
The domain is {-9,-4,3,9}
The range is {2}
Y = x^2 - 6x + 7
a = 1
b = -6
c = 7
Before you get the A.O.S, you must first solve for the vertex.
The vertex formula is \frac{-b}{2a}
Plug in the numbers:
-(-6) / 2(1)
--6 = 6 and 2*1 = 2
6/2
Vertex (or x) = 3
Now you have to plug in the x in order to find the vertex (or y)
Your equation should now look like this;
y = (3)^2 - 6 (3) +7
Solve each part separately and then add it up...
3^2 = 9
-6 * 3 = -18
+7
9 - 18 + 7
A.O.S (or y) = -2
Answer:
25.1 inches
Step-by-step explanation:
Radius of the circle = 4 inches
We have to calculate the value of Circumference of the circle.
The formula to calculate the circumference is:
Circumference = 2πr
We have to use π = 3.14, as said in the question:
So using the values, we get:
Circumference = 2 x 3.14 x 4 = 25.12 inches
Number of decimals in radius is zero, so we have to round the answer to one decimal place as said in the question.
Therefore, the circumference of the circle rounded to one decimal place will be 25.1 inches
Given,
SP~QP
SR~QR
In ∆SRP and ∆QRP
SP~QP (given)
SR~QR (given)
PR=PR (common)
Therefore,
∆SRP~∆QRP by SSS congruence rule.
