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Anettt [7]
3 years ago
11

Determnine if each table shown below represents a function or not.

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

Table 1 does not represent a function.

Table 2 does not represent a function.

Step-by-step explanation:

                                                 Table 1

Input (x)               1             3          5              5           9        

Output (y)             7            16         19             20       28

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

Table 1 indicates that x = 5 is repeated twice. In other words, the input x = 5 is duplicated and we know that we can not have duplicated inputs as there should be only 1 output for each input.

Therefore, table 1 does not represent a function.

                                              Table 2

Input (x)               0.5         7          7               12        15      

Output (y)              1           15         10             23        30

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

Table 2 indicates that x = 7 is repeated twice. In other words, the input x = 7 is duplicated and we know that we can not have duplicated inputs as there should be only 1 output for each input.

Therefore, table 2 does not represent a function.

Conclusion:

We have concluded that both tables do not represent the function.

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Let 3.27<<5.89 represent an interval on the number line. Find the value that is in the middle of the interval.
laila [671]

Answer:

The middle value of the interval is 4.58

Step-by-step explanation:

Consider the provided interval.

We need to find the value that is in the middle of the interval.

We can find the middle value of the interval by adding the upper and lower limit and divide the sum of the upper and lower limits by 2.

Here the upper limit is 3.27 and lower limit is 5.89.

\frac{3.27+5.89}{2}=\frac{9.16}{2}=4.58

Hence, the middle value of the interval is 4.58

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the angle 4pi/5 in quadrent 2

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3 years ago
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Find the volume of a cylinder if it is 2 feet tall and has a diameter of 1.5. Use 3.14 for pi.
olga55 [171]

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3.5325

Step-by-step explanation:

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Suppose f and g are continuous functions such that g(6) = 6 and lim x → 6 [3f(x) + f(x)g(x)] = 45. Find f(6).
aleksandr82 [10.1K]
Since g(6)=6, and both functions are continuous, we have:

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if a function is continuous at a point c, then lim_{x \to c} f(x)=f(c), 

that is, in a    c ∈  a continuous interval, f(c) and the limit of f as x approaches c are the same.


Thus, since lim_{x \to 6} f(x)=5, f(6) = 5


Answer: 5


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4 years ago
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