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2 years ago

X on the top and 24 on the bottom 11 on the top 6 on the bottum

Mathematics

2 answers:

azamat2 years ago

8 0

Answer:

x = 44

Step-by-step explanation:

this is a proportion which you can solve by cross-multiplying:

6x = 24·11

6x = 264

x = 264/6

x = 44

sp2606 [1]2 years ago

6 0

Answer:

Step-by-step explanation:

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From a group of 11 people, 4 are randomly selected. What is the probability the 4 oldest people in the group were selected

asambeis [7]

Answer:

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

<em>Probability = expected number of outcome/Total number of outcome</em>

If there are group of 11 people, then the total outcome of events will be 11

If we are to select 4 oldest people from the group, then the expected outcome is 4.

Hence, the probability that the 4 oldest people in the group were selected is 4/11.

3 0

3 years ago

Distance between (-4,4) and (2,4)

9966 [12]

For this case we have that by definition, the distance between two points is given by:

$d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}$

We have to:

$(x_ {1}, y_ {1}) = (- 4,4)\\(x_ {2}, y_ {2}) = (2,4)$

Substituting:

$d = \sqrt {(2 - (- 4)) ^ 2+ (4-4) ^ 2}\\d = \sqrt {(2 + 4) ^ 2 + (4-4) ^ 2}\\d = \sqrt {(6) ^ 2 + (0) ^ 2}$

$d = \sqrt {36}\\d = 6$

ANswer:

$d = 6$

6 0

3 years ago

Read 2 more answers

If augustin has 1/4 as many cards as mateo.Mateo has 1/2 as many cards as amaro .Who has the most cards?

disa [49]

Let Amaro has x number of cards,
Mateo = 1/2x
Augustin = 1/4 x 1/2x = 1/8x

Answer: Amaro has the most cards.

4 0

3 years ago

4. A group of friends rents a boat to spend an afternoon on a lake. The boat rental has a flat fee of $180 for up to three hours

OverLord2011 [107]

Answer:

it is D c= 180 + 50h + 20p

Step-by-step explanation:

c is the total cost and the boat is 180 but for additional hour it would be +$50

now the first four passenger is free but if another person comes on then it would be +$20 hope this help

5 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

6 0

2 years ago