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3 years ago

A therate ticket cost £63 plus a booking fee of 3% what is the total price of the ticket

Mathematics

1 answer:

joja [24]3 years ago

5 0

Answer:

Total amount of ticket free = £64.89

Step-by-step explanation:

Given:

Cost of theater ticket = £63 plus

Booking fee of theater ticket = 3%

Find:

Total amount of ticket free

Comutation:

Total amount of ticket free = Cost of theater ticket + Booking fee of theater ticket

Total amount of ticket free = 63 + 3%

Total amount of ticket free = 63 + 1.89

Total amount of ticket free = 64.89

Total amount of ticket free = £64.89

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Question 6 (1 point)

alekssr [168]

Answer: i dont know the answer to this qisetion

Step-by-step explanation:

4 0

3 years ago

Which one of the following examples represents a repeating decimal?

Harlamova29_29 [7]

What are the options

5 0

3 years ago

Help me with 24,26,28, and 30 please.

Novay_Z [31]

24)
The number 1/10 can be expressed as a decimal by dividing the top number by the bottom.
1/10=0.1
0.8>0.1
0.8>1/10

26)
The number 3/5 can also be expressed as a decimal, using the method I described for 24.
3/5=0.6
0.6>0.35
3/5>0.35

28)
The number 2/5 can also be expressed as a decimal.
2/5=0.4
0.4>0.3
2/5>0.3

30)
The number 1/6 cannot be expressed as a decimal. So, express 0.2 as a fraction.
0.2=2/10=1/5
1/5=6/30
1/6=5/30
6/30>5/30
0.2>1/6

Hope this helps!

8 0

3 years ago

According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

$P(X < 4) + P(X \geq 4) = 1$