Step-by-step explanation:
We first Find the Slope of the line y=2x+3
The Slope Intercept Form of the equation of a given line is:
y=mx+c
where m is the Slope of that line, and c is the Y intercept.
For this line, the Slope is 2
So the Slope of the line PARALLEL to y=2x+3 will also be 2. And we are given that it passes through the point (2,6)
The Point-Slope form of the Equation of a Straight Line is:
(y−k)=m⋅(x−h)
m is the Slope of the Line
(h,k) are the co-ordinates of any point on that Line.
Here, we have been given the coordinates (h,k) of 1 point on that line as (2,6)
And the Slope m is 2
Substituting the values of h,k and m in the Point-Slope form, we get
(y−2)=(2)⋅(x−6)
(y−2)=2⋅(x-6)
y−2=2x -12
y=2x -12 +2
y=2x-10
The graph will look like
graph{y=2x -10 10 [10, -10, 5, - 5]}
