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2 years ago

Who know the answer to this

Mathematics

1 answer:

Slav-nsk [51]2 years ago

8 0

B bbbbbbbbbbbbbbbbbb

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At a high school baseball game, adult tickets sold for $9 and student tickets sold for $6.50 per ticket.

vladimir2022 [97]

Answer:

answer is attached in the figure below hope it helps please mark it as brainlist

3 0

2 years ago

What would be the answer please explain

sp2606 [1]

Using the line of the best fit, the predicted student's score in English test is 48

<h3>How to determine the student's score in English?</h3>

From the question, we have:

Mathematics score = 60

The scores in English tests are plotted on the y-axis.

On the given graph, we have:

(x,y) = (60,48)

This means that when x = 60, the value of y is 48

This in other words means that the student's score in English test is 48

Read more about line of best fit at:

brainly.com/question/17261411

#SPJ1

6 0

1 year ago

Please help meh i dont know the answer

Savatey [412]

Answer:

3 inches

Step-by-step explanation: An equilateral triangle means all 3 sides are the same length.

A square also have the same length for all 4 sides.

So each side of the square is 6cm, to find the perimeter you do 6*4=24.

then divide the square's perimeter by 3 since triangle have 3 sides. 24/3=8

so each side of the triangle will be 8cm

7 0

2 years ago

The population of a city is 2500. If the number of males is 240 more than the number of females how many males and females are t

Eddi Din [679]

1130 females, 1,370 males

7 0

2 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

2 years ago