As the graph approach negative infinity the graph move to positive infinity as the graph approach positive infinity the graph move to negative infinity
I can’t solve it sorry....................................................<3
Step-by-step explanation:
0 slope means it has in x.
so the equation is y=-1, because that is the coord for the points'y axsis
Given the function. y = 3x + 5
For, x = -3; y = 3(-3) + 5 = -9 + 5 = -4
For x = 1; y = 3(1) + 5 = 3 + 5 = 8
For x = 4; y = 3(4) + 5 = 12 + 5 = 17
Thus the table representing the function is the table with: -3, 1 and 4 as x-values and -4, 8, 17 as y-values.
For x = 0; y = 3(0) + 5 = 0 + 5 = 5
For y = 0; 0 = 3x + 5; 3x = -5 and x = -5/3
Thus the graph of the function is a straight line passing through points (0, 5) and (-5/3, 0).
To illustrate the fuction as a word statement we say that y is five more than three times x
From the given descriptions, the graph does not represent the graph of y = 3x + 5.
Therefore, the one that does not describe the same situation is the graph.
I think the perimeter is 64. If you divided the 4 sides of the window by 256, you get 64. Sorry if it's not right. I hope it is. c;
