A couple invested $6,000 of his $20,000 lottery earning in bonds. How much do they have left to invest in stocks?

tankabanditka [31]

Answer:

Q1)

Rx = 3

in this reflection, the image has been reflected along the x = 3 line. then all the points on the image are reflected along this vertical line. the distance between each point and the vertical line is noted and by that same distance its moved to the opposite side of the vertical line, while the y coordinates stay the same.

A(2,-5)- x coordinate is 2, its 1 unit away from x=3, it should move by 1 unit to the other side of x = 3, then x = 4. y stays as it is.

A' - (4,-5)

B(-4,6) - distance from x = 3, is (-4-+3) is seven units, moves by 7 units to the other side

B' (10,6)

C(3,1) = distance from 3 = 0, therefore the point stays at is,

C' (3,1)

Q2)

next is a translation, in translation the size nor shape changes, each point in the original image moves the same distance in the same direction.

T (3,-6) (x,y) = this means that the x coordinates move by +3 points to the right and y coordinates move downwards by 6 units

A (2,-5) ---> (2+3,-5-6)

A' (5,-11)

B (-4,6) ---> (-4+3,6-6)

B' (-1,0)

C (3,1) ---> (3 + 3, 1-6)

C' (6,-5)

Q3)

r(90°,0)

this is a rotation done in the clockwise direction. then the image takes a rotation to the right direction around the origin.

then the x, y coordinates of the preimage become ;

(x,y) = (y,-x)

A(2,-5) --> A' = (-5,-2)

B(-4,6) ---> B' = (6,4)

C(3,1) ---> C' = (1,-3)

7 0

3 years ago

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I really need help so i need you to help me with my homework so I can bring it back on Friday and it is done so I can get a grad

Yuri [45]

So what's the homework?

8 0

3 years ago

In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2. Section 05.01 Ex

jasenka [17]

Answer:

95% confidence interval for the mean efficiency is [84.483 , 85.517].

Step-by-step explanation:

We are given that in a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2.

So, the pivotal quantity for 95% confidence interval for the population mean efficiency is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\mu$ = sample average efficiency = 85

$\sigma$ = sample standard deviation = 2

n = sample of motors = 60

$\mu$ = population mean efficiency

So, 95% confidence interval for the mean efficiency, $\mu$ is ;

P(-2.0009 < $t_5_9$ < 2.0009) = 0.95

P(-2.0009 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.0009 ) = 0.95

P( $-2.0009 \times {\frac{s}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

P( $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ]

= [ $85 -2.0009 \times {\frac{2}{\sqrt{60} }$ , $85 +2.0009 \times {\frac{2}{\sqrt{60} }$ ]

= [84.483 , 85.517]

Therefore, 95% confidence interval for the population mean efficiency is [84.483 , 85.517].

8 0

3 years ago

Which property of equality is used to solve -9.5=x/1.6

AURORKA [14]

Answer:

x=-15.2

Step-by-step explanation:

8 0

3 years ago

14. A $40,000 loan at 4% dated June 10 is due to be paid on October 11. Calculate the amount of interest (assume ordinary intere

Allisa [31]

D) $546.67

Hope this helped!

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3 years ago

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