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Leto [7]
3 years ago
5

Quadratic functions whose zeros are -2 and -9

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Answer: f(x)=x^{2} +11x+18

Step-by-step explanation:

You might be interested in
in a game using two dice, a person wins if the outcome is a prime number. Find the probability of winning.
AlexFokin [52]

Answer:

45% I think because prime numbers are 5/ the 11 possible numbers when rolling two die

7 0
3 years ago
The perimeter of an isosceles triangle is 65 centimeters. Find the length of the two equal sides when each is 10 centimeters lon
natita [175]

Answer: the length of each of the two equal sides is 25 centimeters

Step-by-step explanation:

Let x represent the length of each of the two equal sides. This means that the total length of the two longer sides is 2x.

Let y represent the length of the third side.

The perimeter of a triangle is expressed as the sum of the length of each side of the triangle. The perimeter of the isosceles triangle is 65 centimeters. It means that

2x + y = 65 - - - - - - - - - 1

Each of the equal sides is 10 centimeters longer than the third side. This means that

x = y + 10

Substituting x = y + 10 into equation 1, it becomes

2(y + 10) + y = 65

2y + 20 + y = 65

2y + y = 65 - 20

3y = 45

y = 45/3 = 15

Substituting y = 15 into x = y + 10, it becomes

x = 15 + 10 = 25

5 0
3 years ago
what is the diameter of 1e-5 meters? PLEASE GIVE ME THE RIGHT ANSWER I WILL MARK U AS BRAINLIEST... :)
joja [24]
I'm not sure exactly what you're asking but 1×10^-5 is .00001. I could be interpreting your question wrong in which case I'm sorry.
4 0
3 years ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
A consumer organization that evaluates new motorcycles customarily reports the number of major defects in each motorcycle examin
koban [17]

Answer:

a) F(2)=0.30

b)P(X>3)=0.7

c)P(2≤X≤5)=0.67

d)P(2<X<5)=0.71

Step-by-step explanation:

a) F(2)=P(X≤2)=0.30

F(2) is given in the probability distribution

b) P(X>3)=1-P(X≤2)=1-F(2)=1-0.3=0.7

P(X>3)=0.7

c)P(2≤X≤5)=?

As we know that P(a≤X≤b)=F(b)-F(a)=P(X≤b)-P(X≤a)

So,

P(2≤X≤5)=P(X≤5)-P(X≤2)=F(5)-F(2)=0.97-0.3=0.67

P(2≤X≤5)=0.67

d)P(2<X<5)=P(1≤X≤4)=P(X≤4)-P(X≤1)=F(4)-F(1)=0.91-0.2=0.71.

P(2<X<5)=0.71

5 0
3 years ago
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