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3 years ago

Quadratic functions whose zeros are -2 and -9

Mathematics

1 answer:

nika2105 [10]3 years ago

6 0

Answer: f(x)= $x^{2} +11x+18$

Step-by-step explanation:

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The answer for your question is w= 2

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3 years ago

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Which answer is equivalent to<br> ??? Help please

grigory [225]

Answer:

$\large\boxed{\dfrac{36}{25}}$

Step-by-step explanation:

$\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}$

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3 years ago

What is <br> Sin A?<br> Cos A?<br> Tan A?

Katyanochek1 [597]

Answer:

See explanation

Step-by-step explanation:

$\sin A = \frac{12}{20} = \frac{3}{5} \\ \\ \cos A = \frac{16}{20} = \frac{4}{5} \\ \\ \tan A = \frac{12}{16} = \frac{3}{4}$

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3 years ago

Find the x-intercept of the line 3x - 9y = 15.

erastovalidia [21]

Answer:

The x-intercept is 5.

Some people prefer you right it as a point (5,0).

Step-by-step explanation:

The x-intercept can be found by setting y=0 and solving for x.

Just like to find the y-intercept you can set x=0 and solve for y.

Let's find the x-intercept.

So we will set y=0 and solve for x:

3x-9y=15

3x-9(0)=15

3x-0 =15

3x =15

Divide both sides by 3:

x =15/3

x =5

So the x-intercept is (5,0).

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horrorfan [7]

Answer:

Step-by-step explanation:

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