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3 years ago

8

Suppose 10 tosses of a coin were all heads, and you switch to a new coin. What is the probability of tossing this new coin and g

etting another head?

1 answer:

tamaranim1 [39]3 years ago

5 0

Answer:

50% or 1/2 Could be 100% but i think it is 50%

Step-by-step explanation:

Because Changing the coin will make no difference.

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For the graph, what is a reasonable constraint so that the function is at least 600? graph of y equals minus 2 times the square

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Answer: it the first option, 0 is less than or equal to x less than or equal to 20

Step-by-step explanation: i took the test :)

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3 years ago

Which value of x makes the qoutient of (5x^5+90x^2-135x)+(x+3)

FinnZ [79.3K]

Answer:

65

Step-by-step explanation:

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3 years ago

Consider the table of values for functions f(x) and g(x).

Vladimir79 [104]

Answer:

D.

Step-by-step explanation:

At x = 2 the 2 rates of change are equal.

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5 0

3 years ago

Please help<br><br>4(4+2x)=x(x+5)

lapo4ka [179]

Answer:

EF = 6

Step-by-step explanation:

Using the secant- secant power theorem, that is

GF × GE = GH × GS

4(4 + 2x) = 5(5 + x) ← distribute both sides

16 + 8x = 25 + 5x ( subtract 5x from both sides )

16 + 3x = 25 ( subtract 16 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Then

EF = 2x = 2 × 3 = 6

3 0

2 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

8 0

3 years ago