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zloy xaker [14]
3 years ago
11

What is 164.50 rounded.

Mathematics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

Rounded to the ones place gives you 165

Step-by-step explanation:

The 5 makes the number bigger by one

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Multiply 3/5 x 35 I don’t know!
aleksley [76]

Answer:The answer is 21

Step-by-step explanation:

simplify-3/5

3/5*35=21


3 0
3 years ago
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Solve: 6 - x=-12 )<br> A) -18 <br>B) C 0 <br>D) 18​
Luda [366]

Answer:

D) 18

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

4 0
3 years ago
Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

6 0
3 years ago
Can you please help and explain I will give brainliest or thanks
Evgesh-ka [11]
9. answer is 12
10. answer is 3.5
11. answer is 23
3 0
3 years ago
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Which of the following numbers is not an integer? A -32 B 80 C 5.81 D 0 O<br>​
larisa [96]

5.81

option C

hope it helps...!!!

3 0
2 years ago
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