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2 years ago

Edwin has £300 in his saving account

Mathematics

2 answers:

Lubov Fominskaja [6]2 years ago

5 0

300 x 1.05 = 315
315 x 1.05 = 330.75
330.75 x 1.05 = 347.2875
347.29

Zepler [3.9K]2 years ago

4 0

Answer:

michin babo-e daehae museun mal-eulhaneungeoya

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I need help answering this question

Advocard [28]

Answer:

$x = 17$

Step-by-step explanation:

Since line m is parallel to line n, therefore:

$(6x + 5) + (5x - 12) = 180$ (consecutive interior angles are supplementary)

Solve for x

$6x + 5 + 5x - 12 = 180$

Add like terms

$11x - 7 = 180$

Add 7 to both sides

$11x - 7 + 7 = 180 + 7$

$11x = 187$

Divide both sides by 11

$\frac{11x}{11} = \frac{187}{11}$

$x = 17$

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2 years ago

Without expanding determinants, Prove that

sasho [114]

Answer:

To prove???

Step-by-step explanation:

i have proved this

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3 years ago

if the two linear functions are represented two different forms the _____ is used to compare the steepness of the two functions&

ELEN [110]

Answer:

Slope

Step-by-step explanation:

Given

The above statement

Required

What compares the steep of linear functions

Literally, steepness means slope.

So, when the slope of the two linear functions are calculated, we can make comparison between the calculated slopes to determine which of the functions is steeper or less steep.

Also:

Higher slope means steeper line

e.g.

4 is steeper than 1

7 0

2 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

2 years ago

Solve quadratic equations by factoring x cubed +3x squared - 4x= 0

Papessa [141]

x cubed +3x squared - 4x= 0
= x^3 + 3x^2 -4x = 0
=x(x^2 +3x -4) = 0
= x (x+4)(x-1) = 0

x = 0
x+ 4 = 0 then x = -4
x - 1 = 0 then x = 1
answer: x = 0, x = -4 and x = 1

8 0

3 years ago

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