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WINSTONCH [101]
3 years ago
13

Jonathan bought a calculator for X$. Cindy bought the same calculator for 3 times more than Jonathan paid for his calculator. Wh

ich expression represents the amount of money Cindy paid for her calculator ?​
Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

3x or 3*x

Step-by-step explanation:

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Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xe^y + ye^z +
LUCKY_DIMON [66]

Answer:

D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}

Step-by-step explanation:

We need to find the directional derivative of the function at the given point in the direction of the vector v.

f(x, y, z)=xe^{y} + ye^{z} + ze^{x} ,point (0, 0, 0) and v=

 

By Theorem: If f is a differentiable function of x , y and z , then f has a directional derivative for any unit vector \overrightarrow{v} = and

D_{\overrightarrow{u}}f(x,y,z)=f_{x}(x,y,z)u_1+f_{y}(x,y,z)u_2+f_{z}(x,y,z)u_3

where \overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}

since,  v=

then \overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}

\overrightarrow{u}=< \frac{6}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{-3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}} >

\overrightarrow{u}=< \frac{6}{\sqrt{54}},\frac{3}{\sqrt{54}},\frac{-3}{\sqrt{54}} >

The partial derivatives are

f_{x}(x,y,z)=e^{y}+ze^{x}  

f_{y}(x,y,z)=xe^{y}+e^{z}

f_{z}(x,y,z)=ye^{z}+e^{x}

Then the directional derivative is

D_{\vec{u}}f(x,y,z)=(e^{y}+ze^{x})(\frac{6}{\sqrt{54}})+(xe^{y}+e^{z})(\frac{3}{\sqrt{54}})+(ye^{z}+e^{x})(\frac{-3}{\sqrt{54}})

so, directional derivative at point (0,0,0)

D_{\vec{u}}f(0,0,0)=(e^{0}+0e^{0})(\frac{6}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{3}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{-3}{\sqrt{54}})

D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}+\frac{3}{\sqrt{54}}+\frac{-3}{\sqrt{54}}

D_{\vec{u}}f(0,0,0)=\frac{6+3-3}{\sqrt{54}}

D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}

3 0
4 years ago
Find the percent one number is of another ?
melamori03 [73]

Answer:


Step-by-step explanation:


4 0
3 years ago
Please help and can you explain
NISA [10]

Answer:

x = 6

Step-by-step explanation:

first you would put them equal because they have the same angle: 9x + 10 = 2x + 52

subtract 10 from both sides: 9x = 2x + 42

subtract 2x from both sides: 7x = 42

divide by 7 on both sides x = 6

hope this helps! :)

7 0
3 years ago
If u had 693 cats and 593 died
Katen [24]

Answer:

you would have 100 cats left

4 0
3 years ago
. A bridge over a river is built in the shape of a parabolic arch. The bridge has a span of 100 feet. The height of the arch is
katen-ka-za [31]

Answer:

The height of the arch at its center is 250/9 or about 27.78 feet.

Step-by-step explanation:

We can write an equation to model the parabolic arch.

Let the left-most point of the arch be the origin (0, 0).

Since the bridge has a span of 100 feet, the right-most point must be (0, 100).

We can use the factored form of a quadratic:

y=a(x-p)(x-q)

Where <em>p</em> and <em>q</em> are the <em>x-</em>intercepts.

Our <em>x-</em>intercepts are <em>x </em>= 0 and <em>x </em>= 100. Hence:

y=ax(x-100)

At a point 40 feet from the center, the height of the arch is 10 feet.

The center is <em>x</em> = 50. So, a point 40 feet from the center can be either <em>x</em> = 10 or <em>x</em> = 90.

So, for instance, when <em>x</em> = 10, <em>y</em> = 10. Substitute and solve for <em>a: </em>

<em />10=10a(10-100)<em />

So:

\displaystyle a=-\frac{1}{90}

The same value will result if we let <em>x</em> = 90 and <em>y</em> = 10.

Hence, our equation is:

\displaystyle y=-\frac{1}{90}x(x-100)

The height of the arch at its center will be when <em>x</em> = 50. Hence:

y(50)=\displaystyle -\frac{1}{90}(50)((50)-100)=\frac{250}{9}\approx 27.78\text{ feet}

4 0
3 years ago
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