Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
Answer:
-11
8 = 2x + 30
8 - 30 = -22
-22 ÷ 2 = -11
x = -11
Also if you place 2×(-11) + 30 you get 8
Answer:
The bottom one to the right. It only reaches 1000 and no higher
Step-by-step explanation:
Answer:
5:1
Step-by-step explanation:
So, we know that 20 fries were large, and 4 were small. So, we just set it up as 20:4 <em>(for every 20 large fries, there are 4 small ones)</em>. However, it needs to be simplified which results in 5:1.
Hope I helped!!
Collection or percolation
