Answer:
Step-by-step explanation:12
Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer: (x-2) (x^2 + 2x + 4)
Step-by-step explanation:
x^3 - 8
x^3 - 2^3
(x-2) * (x^2+x * 2 + 2^2)
(x-2) (x^2 + 2x + 4)
Answer:
Multiply 8x6 and subtract 2 and 3
Step-by-step explanation:
8x6=48
48-3=45
45-2=43