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dezoksy [38]
3 years ago
15

H/ 1/2 = 6 h= ? PLEASE HELP ASAP! I REALLY NEED THIS!

Mathematics
2 answers:
ad-work [718]3 years ago
8 0

Answer:

h = 3

Step-by-step explanation:

Dividing by a fraction is the same as multiplying by its reciprocal.

So h / (1/2) is the same as h * 2 or 2h

2h = 6

Divide both sides by 2 to isolate the variable h.

2h/2 = 6/2

h = 6/2

h = 3

Mademuasel [1]3 years ago
4 0
Six times one half...so the answer us 3. Just reverse the equation to find it
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If u answer ill give brainlist
makkiz [27]

Answer:

120; 643 units squared

Step-by-step explanation:

Perimeter: Add all the sides, so 120 units

_________________________________

Area: First multiply 19 by 24 for the first shape within this other shape, so That equals 456 units squared. Since we know that one whole side is 36 we can subtract 19 from it to get the lower side of the smaller shape and then multiply that by 11. So the smaller side ends up being 17. So 17 times 11 equals: 187 units squared. Then just add the areas together 187+456=643 units squared.

3 0
3 years ago
Let h = for 0   0.01 m, and h = for   0.01 m. (a) find j everywhere. (b) what is j at  = 0? (c) is there a filamentary cu
Katarina [22]
????????????????????????????
4 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
Can someone help me on this question
dexar [7]
It’s an obtuse triangle, this is because none of the sides/angles are equal to one another. Hope this helped you
3 0
3 years ago
Need help solving for x
yawa3891 [41]

Answer:

9.2

Step-by-step explanation:

The given triangle is a right angled triangle. To solve for any of the side length of such triangle, apply the trigonometry ratio formula which can easily be remembered as SOHCAHTOA.

SOH is Sin θ = opposite/hypothenuse,

CAH is Cos θ = Adjacent/hypotenuse

TOA is Tan θ = Opposite/adjacent

Thus, in the right triangle given, we have:

θ = 38°

Opposite side to the given angle = x

Hypotenuse = 15

We're going to use, sin θ = opposite/hypotenuse

Sin(38) = x/15

Multiply both sides by 15 to solve for x

15*sin(38) = x

15*0.616 = x

9.24 = x

<em>x ≈ 9.2 (to nearest tenth)</em>

3 0
3 years ago
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