132.55=5(.04m+2+.7+0.1(21.7))>>>m=66
Answer:
The perimeter of a rhombus with diagonals of 12 feet and 18 feet would be 60 feet.
Step-by-step explanation:
Perimeter of a rhombus: S1 + S2 + S3 + S4 = answer. (S stands for side.)
12 ft. + 18 ft. + 12 ft. + 18 ft. = 60 ft.
The value would be 4.
First, you have to do 4 + 3 because it's in parenteces. This equals 7
Secondly, you have to do 2 x 7, which is 14.
Last you have to do 18 - 14 which is 4.
Answer:
<h2>m∠ABD = 20°</h2>
Step-by-step explanation:
If m∠ABC = 40° and BD is the bisector of ∠ABC, then
(1) m∠ABD = m∠DBC
(2) m∠ABC = m∠ABD + m∠DBC
From (1) and (2) we have:
m∠ABC = 2m∠ABD
Therefore
2m∠ABD = 40° <em>divide both sides by 2</em>
m∠ABD = 20°
