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3 years ago

Pls help I don’t understand

Mathematics

2 answers:

Eva8 [605]3 years ago

6 0

What’s the question

fredd [130]3 years ago

6 0

What is the question

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A lock has two digit numeric code, with the numbers 1 through 7 available for each digit of the code. Note that numbers can be r

lubasha [3.4K]

If there is 2 digits and 7 numbers the combos would be:
1,1 2,1 3,1 4,1 5,1 6,1 7,1
1,2 2,2 3,2 4,2 5,2 6,2 7,2
1,3 2,3 3,3 4,3 5,3 6,3 7,3
1,4 2,4 3,4 4,4 5,4 6,4 7,4
1,5 2,5 3,5 4,5 5,5 6,5 7,5
1,6 2,6 3,6 4,6 5,6 6,6 7,6
1,7 2,7 3,7 4,7 5,7 6,7 7,7

Therefore there are 49 possible combinations :)

7 0

2 years ago

Is f(x) continuous at x equals 4? Why or why not? A. No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit

soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

continuous at x=4? Why or why not? Choose the correct answer below.

Answer:

(D) Yes, f(x) is continuous at x = 4 because $Lim_{x \to 4}f(x)=f(4)$

Step-by-step explanation:

Given the function:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

A function to be continuous at some value c in its domain if the following condition holds:

f(c) exists and is defined.

$Lim_{x \to c}$ f(x)$ exists.

$f(c)=Lim_{x \to c}$ f(x)$

At x=4

$f(4)=\dfrac{1}{4}*4+1=2$

$Lim_{x \to 4}f(x)=2$

Therefore: $Lim_{x \to 4}f(x)=f(4)=2$

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0

3 years ago

Find the scale factor that was used to create the dilaton below

Ne4ueva [31]

Let:

$k\cdot IW=I^{\prime}W^{\prime}$

Where:

k = scale factor

IW = 12

I'W'= 8

so, solving for k:

$\begin{gathered} k=\frac{I^{\prime}W^{\prime}}{IW} \\ k=\frac{8}{12}=\frac{2}{3} \end{gathered}$

3 0

1 year ago

A landscape designer has to construct a rectangular flower bed with a perimeter of 100 feet and the maximum possible area. What

Alinara [238K]

9514 1404 393

Answer:

625 square feet

Step-by-step explanation:

The greatest area of a polygon with a given perimeter is that of a regular polygon. A regular rectangle is one that has all sides the same length -- a square. The side length of a square with 100 ft perimeter is 25 ft. The area of a square with such a side length is

A = (25 ft)² = 625 ft²

The maximum possible area is 625 ft².

In the attached, x is the length of one side. The area versus side length is plotted. The maximum is seen to be 625 ft² for a side length of 25 ft.

8 0

3 years ago

Put in order by least to greatest. 1,0.7,1/10

Finger [1]

Answer:

1/10, 0.7, 1

Step-by-step explanation:

1/10=0.1

0.7=7/10

1=1/1=1.0

3 0

3 years ago

Read 2 more answers