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riadik2000 [5.3K]

3 years ago

7

Need help please it’s due today show work

1 answer:

fiasKO [112]3 years ago

3 0

Answer:

c) +20

Step-by-step explanation:

10 colder goes down

so 30-10= 20

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A polynomial function can be written as (x + 1)(x + 4)(x – 7). What are the x-intercepts of the graph of this function?

attashe74 [19]

Answer:

fourth option

Step-by-step explanation:

Given

f(x) = (x + 1)(x + 4)(x - 7)

To find the x- intercepts let f(x) = 0, that is

(x + 1)(x + 4)(x - 7) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x + 4 = 0 ⇒ x = - 4

x - 7 = 0 ⇒ x = 7

x- intercepts are (- 1, 0 ), (- 4, 0 ), (7, 0 )

6 0

3 years ago

What is the solution of the equation 3x + 5 + 2x - 12

ss7ja [257]

Answer:

7/5

Step-by-step explanation:

3x + 5 + 2x - 12 = 0

5x - 7 = 0

5x = 7

x = 7/5

5 0

2 years ago

Read 2 more answers

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago

What multiplies to negative 9 and adds to negative 3

natima [27]

4.8541019662497 + 1.8541019662497 = -3

<span>-4.8541019662497 x 1.8541019662497 = -9</span>

4 0

3 years ago

Evaluate using distributive property -7/3*5/9+13/3+4/9*-7/3

andre [41]

-7/3*5/9+13/3+4/9*-7/3=2

6 0

3 years ago