Question

The test scores of a geometry class are given below. 90, 75, 72, 88, 85 The teacher wants to find the variance for the class population. What is the value of the numerator of the calculation of the variance? Variance: sigma squared = StartFraction (x 1 minus mu) squared (x 2 minus mu) squared ellipsis (x N minus mu) squared Over N EndFraction -160 -6 16 258.

Answer 1

The value of the numerator of the calculation of the variance is 258, the correct option is D.

Given

The test scores of a geometry class are given below. 90, 75, 72, 88, 85.

What is a variance?

Variance is the expected value of the squared variation of a random variable from its mean value, in probability and statistics.

The mean of the test scores of a geometry class is;

$\rm Mean = \dfrac{90+75+72+88+85}{5}\\\\ Mean =\dfrac{ 410}{5}\\\\Mean =82$

The variance is given by;

$\rm Variance =\dfrac{(90 - 82)^2 + (75 - 82)^2 + (72 - 82)^2 + (88 - 82)^2 + (85 - 82)^2}{5}\\\\Variance = \dfrac{8^2+7^2+(-10)^2+6^2+3^2}{5}\\\\Variance=\dfrac{64+49+100+36+9}{5}\\\\Variance = \dfrac{258}{5}$

Hence, the value of the numerator of the calculation of the variance is 258.

To know more about variance click the link given below.

brainly.com/question/7635845