The correct answer is:
DNA template 3'– ……… –5'
RNA transcript 5'– ……… –3'
Protein product H2N– ……. –COOH
In nucleic acids, DNA and RNA 5’ end refers to phosphate group attached to the 5′ carbon of the ribose ring, while 3’ end refers to the ribose -OH substituent. Nucleic acids can only be synthesized in the 5′-to-3′ direction, which means that the DNA template is 3’—5’. Translation of the protein by the ribosome will also proceed in a 5′ to 3′ direction, which means that the mRNA template is 3’—5’.
The protein during the synthesis is extend from its N terminus toward its C terminus.
Answer:
The correct answer is option d. "phosphorylation of glucose".
Explanation:
The phosphorylation of glucose is one of the most important catabolic reactions that allow to obtain energy from sugars. This reaction is the first step of glycolysis and avoid cells to lose sugars by diffusing back to its transporter. The phosphate used to phosphorylate glucose comes from the hydrolysis of one of the three phosphate of adenosine triphosphate. Therefore, phosphorylation of glucose is a processes where ATP hydrolysis is directly involved.
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Answer:
<u><em>True</em></u>
Explanation:
<u><em>Most gymnosperms have reproductive structures called cones. Male cones produce pollen. Female cones contain at least one ovule. An ovule is a structure that contains an egg cell. After being fertilized, the ovule develops into a seed.</em></u>
Lively is your answer.
Hope this helped! (:
