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PolarNik [594]
3 years ago
11

(30PTS) What are the slopes of the asymptotes of a hyperbola with equation x^2/2^2-y^2/6^2=1

Mathematics
2 answers:
Akimi4 [234]3 years ago
4 0

Answer:

2x2−3y2=6or2x26−3y26=1 or. x23−y22=1or(x−0)2(√3)2−(y−0)2(√2)2=1. This is standard form of the equation of a hyperbola with center.

Step-by-step explanation:

c2 = a2 + b2. Every hyperbola has two asymptotes. A hyperbola with a horizontal transverse axis and center at (h, k) has one asymptote with equation y = k + (x - h) and the other with equation y = k - (x - h).

Crazy boy [7]3 years ago
4 0

Answer:

A.

(3,-3)

Step-by-step explanation:

edge 2020 2021

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