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3 years ago

(30PTS) What are the slopes of the asymptotes of a hyperbola with equation x^2/2^2-y^2/6^2=1

Mathematics

2 answers:

Akimi4 [234]3 years ago

4 0

Answer:

2x2−3y2=6or2x26−3y26=1 or. x23−y22=1or(x−0)2(√3)2−(y−0)2(√2)2=1. This is standard form of the equation of a hyperbola with center.

Step-by-step explanation:

c2 = a2 + b2. Every hyperbola has two asymptotes. A hyperbola with a horizontal transverse axis and center at (h, k) has one asymptote with equation y = k + (x - h) and the other with equation y = k - (x - h).

Crazy boy [7]3 years ago

4 0

Answer:

(3,-3)

Step-by-step explanation:

edge 2020 2021

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suppose the linear regression line y= 2.4x + 3.1 predicts the time,in minutes it takes you to be served at a food stand if there

Scorpion4ik [409]

Answer:

Just substitute "x" with "3".

Step-by-step explanation:

y = 2.4x + 3.1

y = 2.4(3) +3.1

y = 7.2 + 3.1

y= 10.3

Answer: 10.3 minutes

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3 years ago

Read 2 more answers

I need a little help :)

Naily [24]

So firstly, square root 9a^2 and 49: $3a+7\sqrt{b}-a+\sqrt{b}$

Next, combine like terms, and your answer will be $2a+8\sqrt{b}$ , or the third option.

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3 years ago

What is 1 2/3 minus -5 2/3 as a fraction

Sati [7]

7 1/3 hope this helps!

7 0

3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

3 years ago

Explain how to add fractions with unlike denominators. Please be as specific as possible.

Gelneren [198K]

Answer:

Look below

Step-by-step explanation:

So I will use an example to try and show you how to do this.

If we have $1/2 + 1/3$ , we know that we don't have like denominators. We can change this by finding one. All we need to do is multiply our denominators. So in our example, that would be $2*3=6$ . Our new denominator would be 6. So now we would have $1/6 + 1/6$ which isn't the same as our old equation. That is because we haven't multiplied our top numbers yet. To do this, we need to multiply the top number by the opposite denominator like so, $3/6+2/6$ .

So our first fraction was

$1/2+1/3$

We then multiplied the whole fraction by the opposite denominator

$3/6+2/6$

Thanks! Hope you choose me for brainliest!!! Have a nice day!

5 0

3 years ago