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PolarNik [594]
3 years ago
11

(30PTS) What are the slopes of the asymptotes of a hyperbola with equation x^2/2^2-y^2/6^2=1

Mathematics
2 answers:
Akimi4 [234]3 years ago
4 0

Answer:

2x2−3y2=6or2x26−3y26=1 or. x23−y22=1or(x−0)2(√3)2−(y−0)2(√2)2=1. This is standard form of the equation of a hyperbola with center.

Step-by-step explanation:

c2 = a2 + b2. Every hyperbola has two asymptotes. A hyperbola with a horizontal transverse axis and center at (h, k) has one asymptote with equation y = k + (x - h) and the other with equation y = k - (x - h).

Crazy boy [7]3 years ago
4 0

Answer:

A.

(3,-3)

Step-by-step explanation:

edge 2020 2021

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Which equation relates the number of triangles in the figure (n) to the perimeter of the figure (p)
WITCHER [35]

Answer:

Option d is correct.

Equation : P=7n+20.

Explanation;

Given the perimeter of each figure is;

Perimeter of triangle is equal to the sum of all the sides of a triangle.

Perimeter of 1 triangle is 21

Perimeter of 2 triangle is 34 and

Perimeter of 3 triangle is 41

Let n be the number of figure and P be the perimeter of the figure;

the only equation which satisfy the given perimeter is;

P=7n+20

Check:

for n =1 which means 1 triangle then;

P =7n+20 = 7 \cdot 1 +20 = 7+20 = 27

for n = 2 , [ i.e 2 triangle]

P =7n+20 = 7 \cdot 2 +20 = 14+20 = 34

and for n =3 [i.e, 3 triangles]

P =7n+20 = 7 \cdot 3 +20 = 21+20 = 41

Therefore, the equation P =7n+20 relates the number of triangles in the figure(n) to the perimeter of the figure(P).


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Step-by-step explanation:

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