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2 years ago

5

How do you know weather two quantities x and y are proportional?

1 answer:

Colt1911 [192]2 years ago

8 0

Answer:

every difference x-y is the same for related pairs of x and y

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Vance is designing a garden in the shape of an isosceles triangle. The base of the garden is 30 feet long. The function y = 15 t

Stella [2.4K]

Answer:

A. 8.66 feet

B. 12.59 feet

C. Area of triangle when $\theta=30$ is 129.9 square feet. Area of triangle when $\theta=40$ is 188.85 square feet. Increasing the angle $\theta$ increases the area.

Step-by-step explanation:

The equation that models the height of the triangle is:

$y=15 Tan \theta$

Where,

$y$ is the height, and

$\theta$ is the angle

A.

When $\theta=30$ , the height is:

$y=15Tan30\\y=8.66$

B. When $\theta=40[/tex\ , the height is:[tex]y=15Tan40\\y=12.59$

C. <em>To find the area of the isosceles triangular shaped garden, we use the </em><em>formula for the area of the triangle</em><em>:</em>

$A=\frac{1}{2}bh$

Where,

A is the area
b is the base, which is given as 30 feet, and
h is the height [8.66 feet when the angle is 30 & 12.59 when angle is 40]

<u>When Vance uses $\theta=30$ , the area is</u>:

$A=\frac{1}{2}(30)(8.66)\\A=129.9$ square feet

<u>When Vance uses $\theta=40$ , the area is</u>:

$A=\frac{1}{2}(30)(12.59)\\A=188.85$ square feet

So we see that when the angle is more, the area is also more.

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2 years ago

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What is 54/3 in simplest form

prohojiy [21]

I got an answer of 18.

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2 years ago

To test the purity of the hydrazine, the chemist collected a sample 1/2000th the volume of the batch produced. If the sample siz

Bad White [126]

If 0.4 liters is 1/2000 of the production batch, then the production batch is 2000 * 0.4 liters

2000 * 0.4 liters = 800 liters

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3 years ago

List all the factor pairs of 40

Zarrin [17]

2x20
1x40
4x10
5x8

All integers these multiply to 40

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2 years ago

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Please help asap, will mark Brainliest xoxo

IgorC [24]

Answer/Step-by-step explanation:

Given, $b(x) = (\frac{6}{7})^{x}$

The table for the function are:

When x = -2

$b(-2) = (\frac{6}{7})^{-2}$

$b(-2) = \frac{1}{(\frac{6}{7})^{2}}$

$b(-2) = \frac{1}{(\frac{36}{49})}$

$b(-2) = 1*\frac{49}{36}$

$b(-2) = \frac{49}{36}$

When x = -1

$b(-1) = (\frac{6}{7})^{-1}$

$b(-1) = \frac{1}{(\frac{6}{7})}$

$b(-1) = 1*\frac{7}{6}$

$b(-2) = \frac{7}{6}$

When x = 0

$b(0) = (\frac{6}{7})^{0}$

$b(0) = \frac{6^0}{7^0}$

$b(0) = \frac{1}{1}$

$b(0) = 1$

When x = 1

$b(1) = (\frac{6}{7})^{1}$

$b(1) = \frac{6}{7}$

When x = 2

$b(2) = (\frac{6}{7})^{2}$

$b(2) = \frac{6^2}{7^2}$

$b(2) = \frac{36}{49}$

3 0

3 years ago