Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
it is when two triangles are similar to each other in every way.
Mainly there are 4 TYPES OF CONGRUENCY.(A.A.S, S.S.S, R.H.S, S.A.S )
0.1875 you must divide 3 by 16 the numerator by the denominator
Answer:
Step-by-step explanation:
True
Answer:
a^4+3a^2-3b^2
Step-by-step explanation:
