2. 38, 42, 77, 47, 74, 51, 48, 41, 82, 72, 74, 129 Median: Q1 Q1: IQR: Outliers:
vitfil [10]
Answer: Heyo! ;D
I think I know how to solve this...
Let me know it this helps out in any way. :D
Median: "To find the median, first you need to list them in order from least to greatest:"
38, 41, 42, 47, 48, 51, 72, 74, 74, 77, 82, 129
"Now, you count starting from both ends and count to the middle. In this case, 51 and 72 are both the medians. However, there can be only one remaining median. So, what we do is add 51 to 72, then divide the sum by 2 to end with the correct median:"
72 + 51 = 123
123 / 2 = 61.5
Outliers: "All are in a pattern, beside the one number that stands out as the outlier in the given list of numbers. 129 is the only number that isn't in sync with the pattern, hence meaning this is the outlier in the sequence of numbers above."
~Artastic~
2X^2 + 4y = 2 * -2^2 + 4 * 3
Your answer is 4.
If this is incorrect, then I am sorry.
The probability of getting heads on the first toss is 1/2 .
Then, the probability of getting heads on the second toss is 1/2 .
Then, the probability of getting heads on the third toss is 1/2 .
The probability of all three things happening is ...
(1/2) x (1/2) x (1/2) = 1/8 = 0.125 = 12.5% .
It would be 9!!!
Hope that helps!!!
Answer:
3. 6
Step-by-step explanation:
X - y = 4 ( Equation 1 )
X + y =8 ( Equation 2 )
equation 1 + equation 2
; 2x = 12
x = 12÷2
x =6
hope it helps ☺️
