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3 years ago

[x + 3y = -4] [2x + 6y = 5]

Mathematics

1 answer:

stealth61 [152]3 years ago

3 0

Step-by-step explanation:

x+3y=-4(eqn1)

x=-4-3y

from (eqn 2)

2(-4-3y)+6y=5

-8-6y+6y=5

y=5+8=13.

y=13

from eqn 1

x+3(13)=-4

x+39=-4

x=-4-39

x=-43.

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How many different license plates are possible if a license plate consists of 2 capital letters followed by 5 digits?

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3 years ago

Read 2 more answers

I’m need this worked out step by step by tonight

Pie

9514 1404 393

Answer:

-3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

-7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

-14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

-9 ≤ 3x ≤ 19

Divide all parts by 3.

-3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

|(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

|f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.