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Gnom [1K]
3 years ago
14

Warren wants to build a rectangular enclosure for his animals. one side of the pen will be against the barn, so he needs no fenc

e on that side. the other three sides will be enclosed with wire fencing. if warren has 500 feet of fencing, you can find the dimensions that maximize the area of the enclosure.
a.let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn). write an function for the area a of the enclosure in terms of w . (hint first write two equations with w and l and
a. solve for l in one equation and substitute for l in the other). a ( w ) = 1/2w
b.what width w would maximize the area? w = ft
c.what is the maximum area? a = square feet
Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0
L +2w = 500
a = lw

a) l = 500 -2w
.. a = (500 -2w)*w


b) The zeros of the above equation are w=0, w=250. The vertex of this quadratic is on the line of symmetry, halftway between the zeros, at w=125 ft.


c) a = (500 -2*125)*125 = 31,250 . . . . square feet
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What is the lcm of 24 and 30
valentinak56 [21]

Answer:

120

Step-by-step explanation:

5 0
3 years ago
Can someone please help me out again?
Veseljchak [2.6K]

Answer:

12, 24, 60

Step-by-step explanation:

-4 goes in to 12 three times, and 6 goes into 12 twice

-4 goes into 24 six times, and 6 goes into 24 four times

-4 goes into 60 fifteen times, and 6 goes into 60 ten times

Hope this helps

8 0
3 years ago
If the value of y varies directly with x when y=50, x=4. What is the value of y when x=2
den301095 [7]

Answer:

Step-by-step explanation:

The general equation for a direct variation is y = k*x

So your first step (usually) is to find k

y = k x

when x = 4

then y = 50

  • y = k*x
  • 50 = k * 4              Divide by 4
  • 50 / 4 = k*4/4
  • 12.5 = k

Now you can find the value of y when x = 2

  • y = k*x
  • k = 12.5
  • x = 2
  • y = ?

y = 12.5 * 2

y = 25

8 0
3 years ago
Does anyone know the answer ?
Delicious77 [7]
The second one it's double.
5 0
3 years ago
Someone help me with this please
anzhelika [568]

for question 1

Area of Base B =45×25 = 1125 cm²

perimeter of base P = 2(45+25) = 140 cm

Height = 15 cm

Using the formula

Surface area = 2B + Ph

A = 2×1125 + 140×15= 4350 cm²

Voume = Bh = 1125×15= 16875 cm³

For question 2,

Area of base = 7× 5/2= 17.5 cm²

Perimeter of base = (7+7+7) = 21 cm

Surface area = 2B + Ph

Surface area of prism = 2×17.5+ 21×10 = 245cm²

Volume = Bh = 17.5×10 = 175 cm³

6 0
3 years ago
Read 2 more answers
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