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Gnom [1K]
3 years ago
14

Warren wants to build a rectangular enclosure for his animals. one side of the pen will be against the barn, so he needs no fenc

e on that side. the other three sides will be enclosed with wire fencing. if warren has 500 feet of fencing, you can find the dimensions that maximize the area of the enclosure.
a.let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn). write an function for the area a of the enclosure in terms of w . (hint first write two equations with w and l and
a. solve for l in one equation and substitute for l in the other). a ( w ) = 1/2w
b.what width w would maximize the area? w = ft
c.what is the maximum area? a = square feet
Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0
L +2w = 500
a = lw

a) l = 500 -2w
.. a = (500 -2w)*w


b) The zeros of the above equation are w=0, w=250. The vertex of this quadratic is on the line of symmetry, halftway between the zeros, at w=125 ft.


c) a = (500 -2*125)*125 = 31,250 . . . . square feet
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Answer:

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Step-by-step explanation:

Number of Men, n(M)=24

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Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

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  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
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P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

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Answer:

The required expression is:

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Please check the attached graph too.

Step-by-step explanation:

The slope-intercept form of the linear or line function

y = mx+b

where

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In our case,

The cost of hiring a taxi consists of a fixed cost of $3. It means the fixed cost of $3 is the initial condition.

Thus, the y-intercept b = 3

It is stated that the cost of per kilometer distance = $0.5

Thus, the rate of change or slope m = 0.5

As y represents the cost and x represents the number of kilometers.

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Step-by-step explanation:

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