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Olegator [25]
3 years ago
10

Mark has, in his kitchen, the ingredients needed to prepare 78 different recipes with two ingredients

Mathematics
1 answer:
pochemuha3 years ago
3 0

Answer:

13 ingredients

Step-by-step explanation:

The number of different recipes that can be made from 2 ingredients = 78

Since there are no two recipes that share the exact same two ingredients ;

The number of recipes in Mark's kitchen is:

nCk = 78

k = Number of ingredients per recipe = 2

n = total number of ingredients in kitchen

Total recipes made = 78

n! / (n-r)!r! = 78

n! / (n - 2)!2! = 78

n(n-1)(n-2)! / (n-2)! * 2 * 1 = 78

n(n - 1) / 2 = 78

n(n-1) = 156

n² - n = 156

n² - n - 156 = 0

Factorize :

n² - 13n + 12n - 156 = 0

n(n - 13) +12(n-13) = 0

(n-13) = 0 ; (n+12) = 0

n = 13 or n = - 12

n cannot be negative

Hence, n = 13

Number of ingredients is 13

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Answer:

D 5x + 13 = 12

Step-by-step explanation:

3 + 5(x + 2) = 12

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5x = -1

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Answer:

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Step-by-step explanation:

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3 years ago
1 Calculator What is the area of this figure? Enter your answer in the box. units²
photoshop1234 [79]

Answer:

44 units²

Step-by-step explanation:

For triangles: (bases and heights of both triangles are equal)

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For trapezoid:

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7 0
3 years ago
Solve for kkk. \dfrac{k}4+ 3= 14 4 k ​ +3=14
masha68 [24]

Answer: k=1

Step-by-step explanation:

Simplify   1/k

    3     2         1

 (((—+2)-(—•k))-4)-(—-2)  = 0

    k     k         k

2.1   Subtracting a whole from a fraction

      2     2 • k

   2 =  —  =  —————

        1       k  

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

1 - (2 • k)     1 - 2k

———————————  =  ——————

     k            k  

Simplify  2/k

 3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

Simplify 3/k

  3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

5.1   Adding a whole to a fraction

 3                      (1 - 2k)

 (((— +  2) -  2) -  4) -  ————————  = 0

    k                         k    

6.1   Subtracting a whole from a fraction

        2     2 • k

   2 =  —  =  —————

        1       k  

7.1   Subtracting a whole from a fraction

3 + 2 • k     2k + 3

—————————  =  ——————

    k           k  

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

        2     2 • k

   2 =  —  =  —————

        1       k  

9.1     Pull out like factors :

  2 - 2k  =   -2 • (k - 1)

10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -2•(k-1)

 ———————— • k = 0 • k

    k    

Now, on the left hand side, the  k  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -2  •  (k-1)  = 0

Equations which are never true:

10.2      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

10.3      Solve  :    k-1 = 0

Add  1  to both sides of the equation :

                     k = 1

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3 years ago
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Goryan [66]

For the given geometric progression, the nth term of the given GP is A_n=2.3^{n-1}.

Option (C) is correct.

What is the Geometric Progression?

Geometric Progression (GP) is a type of sequence in mathematics in which each succeeding term is produced by multiplying each preceding term by a fixed number known as a common ratio. This progression is also known as a pattern-following geometric sequence of numbers.

The given sequence is 2, 6, 18, 54

here the first term(a) = 2 and the common ratio(r) = 6/2 =3

Then by using the formula for the nth term of a GP, we get

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Hence the nth term of the given GP is A_n=2.3^{n-1}.

To learn more about Geometric progression, visit:

brainly.com/question/12006112

#SPJ4

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