Answer:
P(≥ 7 males) = 0.0548
Step-by-step explanation:
This is a binomial probability distribution problem.
We are told that Before 1918;
P(male) = 40% = 0.4
P(female) = 60% = 0.6
n = 10
Thus;probability that 7 or more were male is;
P(≥ 7 males) = P(7) + P(8) + P(9) + P(10)
Now, binomial probability formula is;
P(x) = [n!/((n - x)! × x!)] × p^(x) × q^(n - x)
Now, p = 0.4 and q = 0.6.
Also, n = 10
Thus;
P(7) = [10!/((10 - 7)! × 7!)] × 0.4^(7) × 0.6^(10 - 7)
P(7) = 0.0425
P(8) = [10!/((10 - 8)! × 8!)] × 0.4^(8) × 0.6^(10 - 8)
P(8) = 0.0106
P(9) = [10!/((10 - 9)! × 9!)] × 0.4^(9) × 0.6^(10 - 9)
P(9) = 0.0016
P(10) = [10!/((10 - 10)! × 10!)] × 0.4^(10) × 0.6^(10 - 10)
P(10) = 0.0001
Thus;
P(≥ 7 males) = 0.0425 + 0.0106 + 0.0016 + 0.0001 = 0.0548
Answer:
Second graph with straight diagonal lines
Step-by-step explanation:
The second graph with straight diagonal lines represents the direct variation
The X and Y axis represents two variables A and B and these two variables in case of second graph with straight lines are directly proportional to each other.
Hence, If value of variable A increases, then value of variable B will also increase
1. To answer the questions shown in the figure atttached, it is important to remember that the irrational number e is aldo called "Euler's number" and you can find it in many exercises in mathematics.
2. Then, the irrational number e is:
e=<span>2.71828
</span>
3. When you rounded, you have:
e=<span>2.718
</span>
4. Therefore, as you can see, the the correct answer for the exercise above is the option c, which is: c. 2.718
The expirmental probability us 28/50
Theoreticaly the probability is 25/50 because that would be half :)
Let
L=event that a selected worker has low risk
H=event that a selected worker has high risk
We need to find
P(HL)+P(LH)
=5*20/(25*24)+20*5/(25*24)
=1/6+1/6
=1/3
