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Free_Kalibri [48]
3 years ago
8

How do I solve this I don't understand any of this at all

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0
I hope this helps you understand the question better!

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Find the area of a triangle with vertices at D(2, 0), E(–1, 0), and F(2, –7).
kati45 [8]
Im suck on the same question 
8 0
3 years ago
Read 2 more answers
Ivy is running errands for her mother. She bikes along straight paths to the supermarket, the bank, and then back home.Find the
chubhunter [2.5K]

The distance between Ivy's house and the supermarket and the distance between the supermarket and the bank:
H&S = 1,014 M; and S&B = 854m. This is resolved using the Sine Theorem.

<h3>What is the calculation backing the above solution?</h3>

Notice that the Angles of a Triangle add up to 180° That is

∠A + ∠B  + ∠C = 180°

Thus,

∠C = 180° - 32° - 109°

= 39°

Recall the Sine Theorem which indicates;

a/SinA = b/SinB = c/SinC

thus given that

AC = 1,523m

We have

AC/SinB = BC/SinA


BC = AC/SinB * SinA

= 1523/Sin109° * Sin32°

BC =854m

Therefore

AC/SinB = AB/SinC
Thus,

AB = AC/SinB * SinC

= 1523/Sin109° * Sin39°
AB ≈ 1,014m

Learn more about the Sine Theorem at;
brainly.com/question/27174058
#SPJ1

5 0
2 years ago
PLEASE HELP LIKE RN, thank you so much
Komok [63]

Answer:

Facts.

Step-by-step explanation:

4 0
3 years ago
How many triangles can be made with the angle 70°, 70°, and 70°
seraphim [82]
Hey there!
Your answer is 0.
All the angles of a triangle must add up to 180 degrees.
However, the sum of these angles is not equal to 180 degrees.
70 + 70 + 70 = 210
210 is not equal to 180.
Hence, no triangles can be made using the angles 70, 70, and 70.
Hope this helps!
7 0
3 years ago
Solve each equation. Check your solution.<br><br><br> 3x 32 = 7x + 28
skad [1K]

Answer:

x= 28 /89

Step-by-step explanation:

3x(32)=7x+28

Step 1: Simplify both sides of the equation.

96x=7x+28

Step 2: Subtract 7 from both sides.

96x   7x+28

−7             −7

89x=28

Step 3: Divide both sides by 89.

89x /89 = 28 /89

6 0
3 years ago
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