How do I solve this I don't understand any of this at all

Mathematics

1 answer:

Svetlanka [38]2 years ago

7 0

I hope this helps you understand the question better!

You might be interested in

Someone help please

Helen [10]

Answer:

Step-by-step explanation:

If you look at the graph, you notice there is no data to determine the slope, but there (0,b) represents the y-intercept. So my guess is, they give you a clue what the slope is already, but if you notice the y-intercept lowers the linear line a few notches because (0,18) is lower than the (0,30). That is what I would choose as the answer

7 0

2 years ago

Va rog e urgent am nevoie de raspuns

Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

= 2 - 1

= 1

f(√3) = 2√3 - 1

*******************************************************

$\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}$

= $\frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})$