Answer:
There are two types of image processing software, raster-based, and vector-based. The CAD and the CAID are just the two vectors based software. However, there is much other software like Adobe Illustrator, Microsoft Publisher, Corel Draw, Photoshop on which you can embark upon, and become an equally good Graphics designer. And hence, you can certainly become a Graphics designer with the CAD experience, however, you should keep in mind that all the great Graphic designers use CAD and CAID. And hence, you should use it sometimes certainly in the future.
Explanation:
Please check the answer section.
C. Assertiveness. Assertiveness is defined as confident and forceful behavior, so it is the only one that makes sense.
A method that returns a string in the form of the hour: minute: second for a given total second that utilizes the given header is as follows:
class Convert {
public static String format(long seconds) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter total seconds: ");
int secs = sc.nextInt();
int hours = secs / 3600;
int minutes = (secs % 3600) / 60;
int seconds = (secs % 3600) % 60;
String timeFormat = hours + ":" + minutes + ":" + seconds;
return timeFormat;
}
}
<h3>What is the String function?</h3>
The string function may be characterized as the type of function in a computer's programming function that may significantly have a non-numerical result.
String functions are typically utilized in computer programming languages in order to manipulate a string or query information about a string successfully.
Therefore, a method that returns a string in the form of the hour: minute: second for a given total second that utilizes the given header is well described above.
To learn more about Header, refer to the link:
brainly.com/question/2329500
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Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
