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andrezito [222]
3 years ago
6

Explain how you can be sure that Pro) O50

Mathematics
1 answer:
Natalija [7]3 years ago
4 0
Can you please explain more
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Posting another free 20 point at 10:30 follow me
Dvinal [7]

Answer:

because they can sense and understand the feeling of human whether they are happy or sad

3 0
3 years ago
Read 2 more answers
How do you do this question?
likoan [24]

Answer:

a) -7/9

b) 16 / (n² + 15n + 56)

c) 1

Step-by-step explanation:

When n = 1, there is only one term in the series, so a₁ = s₁.

a₁ = (1 − 8) / (1 + 8)

a₁ = -7/9

The sum of the first n terms is equal to the sum of the first n−1 terms plus the nth term.

sₙ = sₙ₋₁ + aₙ

(n − 8) / (n + 8) = (n − 1 − 8) / (n − 1 + 8) + aₙ

(n − 8) / (n + 8) = (n − 9) / (n + 7) + aₙ

aₙ = (n − 8) / (n + 8) − (n − 9) / (n + 7)

If you wish, you can simplify by finding the common denominator.

aₙ = [(n − 8) (n + 7) − (n − 9) (n + 8)] / [(n + 8) (n + 7)]

aₙ = [n² − n − 56 − (n² − n − 72)] / (n² + 15n + 56)

aₙ = 16 / (n² + 15n + 56)

The infinite sum is:

∑₁°° aₙ = lim(n→∞) sₙ

∑₁°° aₙ = lim(n→∞) (n − 8) / (n + 8)

∑₁°° aₙ = 1

8 0
3 years ago
Using this formula, how many sides does a polygon have if the sum of the interior angles is 1,260°? Round to the nearest whole n
nikdorinn [45]

Answer:

9 Sides

Step-by-step explanation:

According to the Question,

  • Given That, The sum of the interior angles(s), in an n-sided polygon can be determined using the formula s=180(n−2), where n is the number of sides

Therefore, The sides do a polygon have if the sum of the interior angles is 1,260°.

Put The Values in Formula, we get

1260=180(n−2)

n-2 = 7

n=9 (9 Sides)  

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B1%7D" id="TexFormula1" title="\frac{x}{x+1}" alt="\frac{x}{x+1}" align="a
navik [9.2K]

Answer:

Because i have no more information i assume you would like it to be solved.

x < -1 or -1/3 < x < 1

4 0
4 years ago
6 1/4 as a decimal number
Musya8 [376]
Answer- 6.25 Your welcome.
4 0
3 years ago
Read 2 more answers
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