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3 years ago

PLEASE IM SO LOST RN Can someone please answer the first 3 questions

Mathematics

1 answer:

kondor19780726 [428]3 years ago

7 0

Answer:

1. Yes it does. It's a function because it pass in the vertical line test, which tell us that if you can draw an vertical line through the graph and this line touches the graph in only one point, it is a function.

2. B. I and II only

3. A. y = 8/7 x +5

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An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.

Lunna [17]

<u>ANSWER</u>

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

See attachment for the graph

<u>EXPLANATION</u>

The standard equation of the vertical ellipse with center at the origin is given by

$\frac{ {x}^{2} }{ {b}^{2} } + \frac{ {y}^{2} }{ {a}^{2} } = 1$

where

${a}^{2} \: > \: {b}^{2}$

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

${a}^{2} - {b}^{2} = {c}^{2}$

$\implies \: 289 - {b}^{2} = 225$

$- {b}^{2} = 225 - 289$

$- {b}^{2} = - 64$

${b}^{2} = 64$

We substitute into the formula for the standard equation to get:

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

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3 years ago

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Converse of corresponding angles theorem

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Select the correct expressions.

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Answer:

9x -9

9(x - 1)

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Answer:

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If u can’t find the answers on here you can always try using the Socratic app

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