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Nutka1998 [239]
3 years ago
10

Which of the following points lie in the solution set to the following system of inequalities? (1 point)

Mathematics
1 answer:
swat323 years ago
5 0

Answer:

the answer is

The point (1, −5) lie in the solution set

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Volume = 154 cm cubic
zheka24 [161]

Cylinder Volume

  • Level : JHS

V = hπr²

154 cm³ = 16 cm × 3.14 × r²

154 cm³ = 50.28 cm × r²

r² = 154 cm³ : 50.28 cm

r² = 3.0625 cm²

r = 1.75 cm

d = 2r

d = 2 × 1.75 cm

d = 3.5 cm

So, the diameter of the Cylinder is 3.5 cm

#LearnWithEXO

8 0
3 years ago
Convert 12 cups to quarts
Trava [24]

Answer: 3 quarts

using the information 1 cup = 0.25 quarts, we can use dimensional analysis or a conversion factor to find the number of quarts in 12 cups.

start by expressing x as your unknown value being the number of quarts

there are 3 quarts in 12 cups

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose a jar contains 15 red marbles and 19 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same
Kay [80]

Answer:    \bold{\dfrac{35}{187}}

<u>Step-by-step explanation:</u>

1st marble  and   2nd marble

 \dfrac{15\ red}{34\ total}       \times        \dfrac{14\ red}{33\ total}           =\dfrac{15\times 14}{34\times 33}=\dfrac{5\times 7}{17\times 11}= \boxed{\dfrac{35}{187}}

8 0
2 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
Please show your work, and have a good day :)
fomenos

Answer:

273x

Step-by-step explanation:

-7x(-8²+25)

8²=64

-7x(-64+25)

-64+25=-39

-7x(-39)

-7×-39=273

273x

7 0
2 years ago
Read 2 more answers
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