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3 years ago

Explain why a polar curve is not always bounded.

1 answer:

8 0

Answer: There are lots of common polar curves that are bounded therefore a polar curve is not always bounded all the time. A polar curve is required to have an unbounded function (right side of r = f(Θ)) to be an unbounded polar. An example of an unbounded curve would be r = Θ for 0 ≤ Θ.

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Mark and Don are planning to sell each other their marble collections at a garage sale. If Don has 1 more than 3 times the numbe

Volgvan

Answer: Mark has 28 marbles while Don has 85 marbles.

Step-by-step explanation:

Let x represent the number of marbles that Mark has.

Let y represent the number of marbles that Don has.

If Don has 1 more than 3 times the number of marbles Mark has, it means that

y = 3x + 1

The total number of marbles is 113. It means that

x + y = 113- - - - - - - - - - - - 1

Substituting y = 3x + 1 into equation 1, it becomes

x + 3x + 1 = 113

4x + 1 = 113

4x = 113 - 1 = 112

x = 112/4

x = 28

y = 3x + 1 = 3 × 28 + 1

y = 85

4 0

3 years ago

Find the fourth term of a geometric sequence if a=6 and r=2. Use the formula an=ar^n-1

Vikentia [17]

Answer:

Step-by-step explanation:

here, we are using an = ar^n-1

so, we have to find a4= ar^4-1 = ar^3

now, putting the given values in the equation,

a4= (6)(2)^3 = 6(8) = 48

therefore, the 4th term is 48.

I have done this question previously on Gauthmath app, you can check that app out, really cool app.

All the best with your exam. 

8 0

3 years ago

The length of a parking lot is 7 yards more than the width.If the area of the parking lot is 98 square yards,find the dimensions

USPshnik [31]

The parking lot is 14 yards long by 7 yards wide.

A = W x L The formula is ....

L = W + 7 The problem tells us that ...

A = W (W + 7)
A = w^2 + 7w
98 = w^2 + 7x
... continue from there

7 0

3 years ago

6(x-2=4(x+3) what does x equal

Delicious77 [7]

Hey mate here is your answer.

➛ 6(x-2) = 4(x+3)

➛ 6x-12 = 4x + 12

➛ 6x - 4x = 12 + 12

➛ 2x = 24

➛ x = $\frac{24}{2}$

⛬ x = 12

4 0

4 years ago

In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th

iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095

applying the given data :

a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

= 61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ = 0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0

3 years ago