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goldenfox [79]
3 years ago
7

Help me with this answer please !

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

pick number 3 I think that's the one

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FIRST PERSON TO ANSWER CORRECTLY GET MARKED BRAINLY
Andru [333]

Answer:

the first one

Step-by-step explanation:

2x+у=3

3x-y=2

6 0
3 years ago
Solve by making a proportion. If seven movie tickets cost $57.40, how much would 5 tickets cost?
emmainna [20.7K]

Answer: $41

work out what one ticket is:

$57.40/7=$8.20

and then multiply by 5

$8.20*5=41

4 0
3 years ago
Suppose that the probability that a child living in an urban area in the United States is obese is 20%. If a social worker sees
Levart [38]

Answer:

The probability the event that none of them are obese is 0.0352.

Step-by-step explanation:

<h3>Binomial distribution:</h3>

A discrete random variable X having to the set {0,1,2,3....,n} as the spectrum, is said to have binomial distribution with parameters n= the number of trial, and p= probability of successes on an individual trial , if the p.m.f of X is given by,

P(X=x)=\left(\begin{array}{c}n\\x\end{array}\right) p^x(1-p)^{n-x} for x=0,1,2,...,n

                =0                               elsewhere.

where 0<p<1 and  n an positive integer,

Given that,

The probability of the event that a child living in an urban area in the united state is obese is 20%.

n=Number of children = 15, p= 20%= 0.20.

The probability the event that none of them are obese is

=P(X=0)

=\left(\begin{array}{c}15\\0\end{array}\right) (0.20)^0(1-0.20)^{15-0}

=0.0352

7 0
4 years ago
Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an
Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as V=g(x), where g(x)=x(6-2x)(8-2x) and 0\le x\le3.

Expand the function to obtain:

g(x)=4x^3-28x^2+48x

Differentiate  wrt  x to obtain:

g'(x)=12x^2-56x+48

To find the point where the maximum value occurs, we solve

g'(x)=0

\implies 12x^2-56x+48=0

\implies x=1.13,x=3.54

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

g''(x)=24x-56, g''(1.13)=24(1.13)-56=-28.88\:

This means the maximum volume occurs at x=1.13.

Substitute x=1.13 into g(x)=x(6-2x)(8-2x) to get the maximum volume.

g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0
4 years ago
Subtract. Express your answer in lowest terms.
natima [27]
6 3/11 good luck :)
7 0
4 years ago
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