Answer: A= 36
Step-by-step explanation:
6+6=12
12+12=24
add 12 and 24=36
Raa that's hard but all I have to do is count how many chicken legs there r n then same w pigs
Let's simplify step-by-step.<span><span><span><span>−12</span>−12</span>−<span>12x</span></span>+6</span><span>=<span><span><span><span><span><span>−12</span>+</span>−12</span>+</span>−<span>12x</span></span>+6</span></span>Combine Like Terms:<span>=<span><span><span><span>−12</span>+<span>−12</span></span>+<span>−<span>12x</span></span></span>+6</span></span><span>=<span><span>(<span>−<span>12x</span></span>)</span>+<span>(<span><span><span>−12</span>+<span>−12</span></span>+6</span>)</span></span></span><span>
=<span><span>−<span>12x</span></span>+<span>−<span>18</span></span></span></span>
Answer:
11,236
Step-by-step explanation:
i think this might be the answer but if it not alseat I try helping
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
