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marysya [2.9K]
2 years ago
7

For question 2, find the x- and y-intercept of the line.

Mathematics
1 answer:
omeli [17]2 years ago
3 0
D. X-intercept is 16; y-intercept is 20.
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Which is greater -3.7 or -3 2/5
lara [203]

Answer:

-3 2/4 is greater that -3.7

Step-by-step explanation:

2/4 is 0.4 and when dealing with negatives so the lower negative is the closest to 0 so the smaller negative is the greatest.

8 0
3 years ago
GEOMETRY!!!! K' (6,5) is the image of K after a reflection in the line y=2. what are the coordinates of K
frutty [35]

Given:

The coordinates of point K' are (6,5).

K' is the image of K after a reflection in the line y=2.

To find:

The coordinates of point K.

Solution:

Let the coordinates of point K are (a,b).

If a figure is reflected over the line y=2, then

(x,y)\to (x,2(2)-y)

(x,y)\to (x,4-y)

Using this formula, the coordinates of image of K are

K(a,b)\to K'(a,4-b)

The coordinates of point K' are (6,5).

K'(a,4-b)=K'(6,5)

On comparing both sides, we get

a=6\text{ and }4-b=5

a=6\text{ and }-b=5-4

a=6\text{ and }-b=1

a=6\text{ and }b=-1

Therefore, the coordinates of point K are (6,-1).

3 0
2 years ago
A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed
Natali [406]

Answer:

t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587  

df=n_{1}+n_{2}-2=8+8-2=14

Since is a one sided test the p value would be:

p_v =P(t_{(14)}>2.587)=0.0108

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

Step-by-step explanation:

Data given and notation

\bar X_{1}=1.17 represent the mean for the sample 1 (25 mil film)

\bar X_{2}=1.04 represent the mean for the sample 2 (20 mil film)

s_{1}=0.11 represent the sample standard deviation for the sample 1

s_{2}=0.09 represent the sample standard deviation for the sample 2

n_{1}=8 sample size selected for 1

n_{2}=8 sample size selected for 2

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if reducing the film thickness increases the mean speed of the film, the system of hypothesis would be:

Null hypothesis:\mu_{1} \leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=8+8-2=14

Since is a one sided test the p value would be:

p_v =P(t_{(14)}>2.587)=0.0108

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

4 0
3 years ago
, Hayley sold 20 tickets to the school play for a total of $225 early bird tickets were $10 and regular price tickets were $15 w
Lady_Fox [76]

Answer:

15 early tickets were sold and 5 regular tickets were sold.

Step-by-step explanation:

Let x be the number of early bird tickets sold and y be the number of regular tickets sold.

Total number of tickets sold = 20

Thus, we can write the equation,

x + y = 20

Cost of early bird ticket = $10

Cost of regular tickets = $15

Total cost = $225

Thus, we can write the equation,

225 = 10x + 15y

We solve the equation by elimination method by multiplying first equation by 10 and subtracting.

10x + 15y-(10x+10y) = 225 - 200\\5y = 25\\\Rightarrow y=5\\x + 5 = 20\\\Rightarrow x = 15

Thus, 15 early tickets were sold and 5 regular tickets were sold.

5 0
3 years ago
Can help me on the question 17!?
dsp73

Answer:

18 feet

Step-by-step explanation:

5 years to 30 years is 6

6x5=30

3x6=18

7 0
2 years ago
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