The probability that the arrow will land on any of them <em>once</em> is 1/4.
The probability that the arrow will land on any of them <em>twice</em> is 1/4 * 1/4. This is because the probability of Event A <em>and</em> Event B is P(B) * P(A).
Based on this:

1/256
Hope this helps, let me know if I missed anything!
So use pythagorean theorem to find the straight distance between hhouses
legs are 6 and 8
a^2+b^2=c^2
6^2+8^2=c^2
36+64=c^2
100=c^2
squrer root both sides
10=c
the distance=10 miles
Answer:
They are compatible
Step-by-step explanation:
The first thing is to say that an "ace" and that it is a "coarse"
"ace" is card number 1. Group A
"coarse" is a type of the deck, found from number 1 to card 13. Group B
Thus:
Calculate A U B:
1 to 13 + 1 of the other types of cards in the deck.
At intersection B:
1 of "coarse"
Therefore, if group A is compatible with group B
I have no clue I would help but have know clue
9514 1404 393
Answer:
no solution
Step-by-step explanation:
The equations describe parallel lines. There are no values of x and y that will satisfy both equations.
In standard form, the two equations are ...
3x +7y = 21
3x +7y = -42 . . . . . with positive leading coefficient
If (x, y) values satisfy the first equation, they cannot satisfy the second equation, and vice versa.