Plssss help. High school mathematics

Find the length of the third side. If necessary, round to the nearest tenth. 6 14

Romashka-Z-Leto [24]

Answer:

≈ 12.6

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the third side, then

x² + 6² = 14²

x² + 36 = 196 ( subtract 36 from both sides )

x² = 160 ( take the square root of both sides )

x = $\sqrt{160}$ ≈ 12.6 ( to the nearest tenth )

8 0

3 years ago

Is 7 1/5 a rational number

kolbaska11 [484]

Yes because when you turn into a decimal it's 7.2

7 0

3 years ago

Read 2 more answers

Write 3.16 as a mixed number in lowest terms

Yakvenalex [24]

$3.16=3 { \frac {16}{100} }== \gt mixed\ number \\ \ \ \ \ \ \ \ \ =3 { \frac {\ 4\ }{\ 25\ } } == \gt lowest\ term$

3 0

3 years ago

Read 2 more answers

Amelie found the solutions of the equation x2 − 1x = 42 to be 6 and −7. Explain why this answer is incorrect. Then, find the cor

cupoosta [38]

I dont know how to solve it but since the answer shows as 6 and -7, if you plug it in as x values, one tiem as 6 and second time as -7 it doesnt equal 42

7 0

3 years ago

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

3 years ago