Plug in x-values and see which one has an incorrect y value.

(x, y)

x=0; y=0+7=7; CORRECT
x=2; y=2+7=9; INCORRECT
x=9; y=9+7=16; CORRECT
x=12; y=12+7=19; CORRECT

The point that is not on the online is (9, 16).

4 0

2 years ago

Jane multiplies her number by three and subtracts 2.

katrin [286]

Answer:

Let the number they chose be 'x'.

Result of Jane = $3x -2$

Result of Elliot = $2x+3$

Given that,

The product of their result = 110

$or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}$

3 0

2 years ago