Answer:
D) use SQL or graphical tools to query the database
Explanation:
To query the database using SQL or graphical tools will help Howie to retrieve bulk of records from the database according to his requirements and it will help to understand and work with the data in a better way than using the data in raw form.
SQL is a language of database used to manipulate and manage the data in the relational database and to query the database.
It is an easy and faster way to query using SQL or graphical tools because no coding is required here.
Different graphical tools are used to present the data in the database in a way that can be easily understood by a person. Different interfaces are provided to visualize the database tables or schema diagrammatically e.g in the form of graphs etc. Different views of the database can be provided to different users according to their requirement and what information they required to be presented.
Answer: Concurrent programs are the programs that execute at the same point of time. They are simultaneous in nature with other concurrent programs.They are executed with the help of threads to achieve the concurrency without the issue of scheduling. They are consider long running programs.
The program that has the low execution time compared with all other programs gets executed first.If the case of no progress is seen then another thread is executed.This type of execution gives the non- deterministic situation in which the possibility of leading completion of any particular program cannot be determined.
Answer:
I assume you want to set the opacity (0-100) depending on the mouse's coordinate on the screen. The variables indicating the mouse's coordinates are <em>mouseX</em> and <em>mouseY</em>.
To achieve this, you will need to divide the mouseX/mouseY (whichever you choose) by 4 to what's called "normalize" it. If your mouse was at 320 for example... Dividing it by four would give you 80, and this works because the bounds that the opacity can be set to is 0-100.
normalized = mouseX / 4
Circle(mouseX, mouseY, 50, fill='navy', opacity=normalized)
...or if you want to do it in one line...
Circle(mouseX, mouseY, 50, fill='navy', opacity=mouseX / 4)
ANSWER 9:
The offset address of an element in row 16 and column 3 = 0100000011 (10 bits address)
Explanation:
The size of bit fields for row and column numbers should be big enough to accommodate the highest possible row and column numbers.
For 57 × 10 matrix M will have 6 bits for rows (26=64 so 6 bits can accommodate 57 values) and 4 bits for columns (24 =16 so 4 bits can accommodate 10 values). For offset address of an element in row 16 and column 3:
6 bits of row address will be the binary value of 16 = 010000
4 bits of column address will be the binary value of 3 = 0011
Now, for offset address of an element in row 16 and column 3 will be the concatenation of row and column address = 010000 concat 0011 = 0100000011 (10 bits address)