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den301095 [7]
2 years ago
11

FREE BRANLEIST URGENT WITH EQUATION!! WILL REPORT AND GET BANNED IF LINKS AND INCORRECT ANSWERS

Mathematics
2 answers:
ser-zykov [4K]2 years ago
6 0

Answer:

ok so a it' probabily 21 or a number between 1-10

Step-by-step explanation:

pickupchik [31]2 years ago
4 0

Answer:

q.10 142 degree

q.11 x=11

q.12 complementary angles

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The temperature last night was 7 degrees. By morning, the temperature dropped 10 degrees. What was the temperature in the mornin
trasher [3.6K]
-3 degrees is the answer
3 0
3 years ago
Read 2 more answers
On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?
Nata [24]

Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

Total number of  students = 445

We need to find the approximate absentee rate that day :

Rate of absentee of that day would be

\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%

Hence, the approximate absentee rate that day would be 8.09%.

5 0
3 years ago
K over 1.5 equals 3 what is k
jeyben [28]

Answer:k=4.5

Step-by-step explanation:4.5/1.5=3

7 0
3 years ago
Consider the sequence 10, 2..
romanna [79]

Answer:  see below

<u>Step-by-step explanation:</u>

1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t_n=\dfrac{t_{n-1}}{10}+1

t₁ = 10

t₂ = 10/10 + 1    = 2

t₃ = 2/10 + 1     = 1.2

t₄ = 1.2/10 + 1   = 1.12

t₅ = 1.12/10 + 1  = 1.112

t₆ = 1.112/10 + 1 = 1.1112

2)  10, 2, -2, -4, -5, -5.5, ...

t_n=\dfrac{t_{n-1}}{2}-3

t₁ = 10

t₂ = 10/2 - 3 =   2

t₃ = 2/2 - 3  =  -2

t₄ = -2/2 - 3 =  -4

t₅ = -4/2 - 3 =  -5

t₆ = -5/2 - 3 = -5.5

8 0
3 years ago
Find the sum of the first one hundred positive integers. see fig 6.26
nignag [31]
Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
s =  \frac{n(n + 1)}{2}
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
8 0
3 years ago
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