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2 years ago

Find the number if 5/6 of it is 55.

Mathematics

2 answers:

kow [346]2 years ago

6 0

Answer:

The unknown number is 66.

Step-by-step explanation:

We know that we need to find the number that is 55 when calculated as 5/6 or the whole number. First, we must divide 55 by 5.

55 ÷ 5 = 11

This means that 1/6 of the unknown number is 11.

Now, let's multiply 11 by 6.

11 x 6 = 66

Therefore, the unknown number is 66.

Hope this helps! :)

Marrrta [24]2 years ago

3 0

Answer:

Step-by-step explanation:

let the x represent the number

5/6 ×X=55

5X =55×6

5X = 330

X =330/5

X = 66

check : (5/6) ×66

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7¼× 8/9×3/4 find the sum

larisa86 [58]

Answer:

Step-by-step explanation:

$7\frac{1}{4}*\frac{8}{9}*\frac{3}{4}=\frac{29}{7}*\frac{8}{9}*\frac{3}{4}\\\\=\frac{29*8*3}{7*9*3}\\\\=\frac{29*2*1}{7*3*1}\\\\=\frac{58}{21}\\\\=2\frac{16}{21}\\$

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2 years ago

If C is the center of the circle, find the measure of KM

stiv31 [10]

Your answer is 160. Sorry about that answer above I laughed reading it hahaha.

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3 years ago

Read 2 more answers

Given log4(3) =0.7925 and log4(5) =1.1610, use log properties to find log4(300).

Ede4ka [16]

Answer:

4.1145

Step-by-step explanation:

You can use the following formula to solve this kind of problems,

$log_{a}(b) + log_{a}(c) = log_{a}(bc)$

So, let's start of with log4_(300). Since the question have already gave log4_(3) =0.7925 and log4_(5) =1.1610. It means that you have to split the 300 into the simplest form where almost all of the numbers are 3 and 5.

$log_{4}(300) = log_{4}(4 \times 5 \times 3 \times 5) \\ = log_{4}(4) + log_{4}(5) + log_{4}(3) + log_{4}(5) \\ = 1 + 1.1610 + 0.7925 + 1.1610 \\ = 4.1145$

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2 years ago

PLS HELP!!

GuDViN [60]

25.69 + .75= $26.44

Hope this helps.

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2 years ago

2x(5+3x)-x find the coefficient of x

s344n2d4d5 [400]

To start, we need to distribute

multiply 2x by everything in the parenthesis

2x (5 + 3x) - x

2x × 5 = 10x

2x × 3x = 6x²

now we have...

10x + 6x² - x

simplify

6x² + 9x

the coefficient of x is 9!

4 0

3 years ago