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sveta [45]
3 years ago
12

The area of a rectangle is the product of its length and width.a rectangular poster has an area of 260 square inches.the width o

f the poster is greater than 10 inches and is a prime number.what is the width of the poster?
Mathematics
1 answer:
mina [271]3 years ago
3 0
\sf 260 = width \times length\\\\ w \ \textgreater \  10; w = prime ~number\\\\\boxed{w = 13}

13 is also divisible into 260.

The width is 13, and the length is 20
You might be interested in
Natalie made blueberry muffins for a bake sale. Each muffin cost her about $0.25 to make. She spent $8.75 to make all of the muf
Inga [223]

Answer:

26.25

Step-by-step explanation:

she sold 35 muffins

8 0
3 years ago
Read 2 more answers
I need the answers for 6,7,8,9,10,11 pls fast
Natalka [10]

Answer:

6) common denominator = 54

7) common denominator = 80

8) common denominator = 108

9) least common denominator = 10

10) least common denominator = 24

11) common denominator = 21


Step-by-step explanation:

6) common denominator of 1/6 , 1/9

example: A/B where A is de numerator and B is the denominator.

common denominators are numbers that have te same composition

1/6 , 1/9 ⇒ if we want to add this fractions we need to find the common denominator.

therefore: (1/6)*(9/9) , (1/9)*(6/6) ⇒ ((1*9)/(6*9)) . ((1*6)/(9*6)) ⇒ 9/54 , 6/54

the common denominator is 54

7) 3/8 , 3/10

(3*10)/(8*10) , (3*8)/(10*8) ⇒ 30/80 , 24/80

common denominator of this two fractions is 80

Note: We can see that the common denominator can be find just by multiplying the denominators. in 7) 6*9=54 and in 8) 10*8=80. This is because in this cases we are asked just for the common denominator

9) 1/9 , 5/12 ⇒ common denominator = 9*12 = 108

10) Least common denominator of 2/5 , 1/10

in this case is the smmallest number that the denominator have in common:

first, from 2/5: denominator=5

multiples of 5: ⇒5, 10, 15, .........

then from 1/10: denominator=10

multiples of 10 ⇒ 10, 20, 30,....

The least common denominator is the smalles number this two denominators have in common. We can see that this number is 10.

There are other ways because you should also think of it as the minimun common denominator. 5 =5*1 and  10 = 2*5 (minimun expresions)

the least minimun denominator willbe the one that includes all de numbers included in their minimum expresion without making it doble (just the amount of times to make the denominator number in each fraction).

therefore we would know that the least common denominator in this fractions is: 1*2*5 = 2*5 = 10

But just have fun and make it simple

10. least common denominator for: 5/6 , 3/8

first: 5/6 ⇒ denominator: 6, so ⇒ 6, 12, 18, 24, 30, 36.....

then: 3/8 ⇒ denominator: 8, so ⇒ 8, 16, 24. 32, 40....

least common denominator for this fractions is ⇒24

or also:

5/6 ⇒ denominator is 6 ⇒ 6=2*3

3/8 ⇒ denominator is 8 ⇒ 8=2*2*2

least common denominator for this fractions is ⇒ 2*2*2*3 =24

11. common denominator of: 1/3 , 2/7

because in this case 3 and 7 are in their minimum expresion ⇔ 3=1*3 & 7=1*7

we can jus find the common denominator by multiplying both denominators:

7*3=21

Hope it helps.

8 0
3 years ago
If y varies directly with x, with k=0.75,what is the value of y when x=12
erma4kov [3.2K]

Answer:

9

Step-by-step explanation:

y=x

y=kx

substitute k for 0.75 and x for 12 in the above equation

y=0.75×12

y=9

7 0
3 years ago
A cylinder has a base diameter of 16 feet and a height of 19 feet. What is its volume in cubic feet, to the nearest tenths place
qaws [65]

Answer:

3820.18

Step-by-step explanation:

5 0
3 years ago
Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis
Mariana [72]

Answer:

45

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by p_1, p_2,...,p_9, and all the sweet dishes by q_1,q_2,...,q_5.

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with q_1 from sweet plates which are (q_1, p_1), (q_1, p_2), ..., (q_1,p_9).

There are 9 plates with q_2 from sweet plates which are  (q_2, p_1), (q_2, p_2), ..., (q_2,p_9).

Similarly, there are 9 plated for each q_3, q_4 and q_5.

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

= 9+9+9+9+9= 9\times5=45

7 0
3 years ago
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