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3 years ago

A gym membership is advertised to cost $630 per year.What is the cost per month of the gym memebership

Mathematics

2 answers:

Rama09 [41]3 years ago

3 0

Answer:

Step-by-step explanation: $630 divided by 12 months is $52.50

stellarik [79]3 years ago

3 0

Answer:$52.50

Step-by-step explanation:

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The top of the cylindrical can shown below has a diameter of 7 centimeters (cm).

Zigmanuir [339]

Answer:

Step-by-step explanation:

3 0

3 years ago

How can you use factoring to solve these three problems?

torisob [31]

You're meant to make one side of the equation equal 0.
For example, the first problem is $2k x^{2}$ + 9k = -7
You'd add 7 to both sides, leaving you with $2k x^{2}$ + 9k +7 =0
And I assume you know how to factor??

3 0

3 years ago

Options are: X=2, Y=3 X=3, Y=2 X= -2, Y=3 X=4, Y=8

tester [92]

Answer:

x = 4, y = 8

Step-by-step explanation:

If the triangles are congruent by the HL Theorem, it means that the hypotenuse and one leg of the right triangle are congruent to the corresponding one leg and hypotenuse of the other.

Thus;

2x - 5 = y - 5 (Eqn 1) and

y - 3 = x + 1 (Eqn 2)

Thus:

Rewrite equation 1

2x = y - 5 + 5

2x = y

Substitute y = 2x in equation 2.

y - 3 = x + 1 (Eqn 2)

2x - 3 = x + 1

Collect like terms

2x - x = 3 + 1

x = 4

Substitute x = 4 in equation 1

2x - 5 = y - 5 (eqn 1)

2(4) - 5 = y - 5

8 - 5 = y - 5

3 = y - 5

3 + 5 = y

8 = y

y = 8

4 0

4 years ago

Does anyone know this??

STALIN [3.7K]

Hi there! The answer is C.

Explanation:
We have the following equation:

$\frac{8}{15} = \frac{x}{6}$
To solve this type of equation (with an x in the denominator of a fraction) we must cross-multiply the numerator and the denominator.

$15 \times x = 8 \times 6$
Multiply

$15x = 40$
Divide both sides by 15.

$x = \frac{40}{15} = 2 \frac{2}{3}$
~ Hope this helps you!

5 0

3 years ago

Read 2 more answers

A tank is in the shape of an inverted circular cone with height 500 ft and base radius 20 ft. It is filled with water to a heigh

SashulF [63]

Answer:

1.338 * 10 ^ 9 lb-ft

Step-by-step explanation:

We have the following information:

Water density 62.4 lb / ft ^ 3

work equals force per distance, like this:

W = F * d

with the information in the statement we can deduce:

20/500 = r / y

r = y / 25

now the differential volume would be:

dv = pi * (r ^ 2) * dy

dv = pi * ((y / 25) ^ 2) * dy

dv = pi * (y ^ 2/625) * dy

weight of slice would be:

62.4 * pi * (y ^ 2/625) * dy

= 0.3136 * y ^ 2 * dy

work for the removal of slice:

(500 - y) * 0.3136 * y ^ 2 * dy

Now the total work is the integral of the previous expression that goes from y = 0 to y = 400

Total work = integral (from 0 to 400) {(500 - y) * 0.3136 * y ^ 2 * dy}

Total work = integral (from 0 to 400) {0.3136 * (500 * y ^ 2 - y ^ 3) dy}

We integrate and we have:

Total work = 0.3136 * ((500/3) * y ^ 3 - (y / 4) ^ 4)

Total work = 0.3136 * ((500/3) * 400 ^ 3 - (400/4) ^ 4) - 0.3136 * ((500/3) * 0 ^ 3 - (0/4) ^ 4)

Total work = 0.3136 * ((500/3) * 400 ^ 3 - (400 ^ 4) / 4)

Total work = 1.338 * 10 ^ 9 lb-ft

5 0

3 years ago